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timurjin [86]
2 years ago
5

Liquid methanol is pumped from a large storage tank through a 1-in.ID pipe at a rate of 3.00gal/mm.

Engineering
1 answer:
mafiozo [28]2 years ago
5 0

a) (i) The kinetic energy rate in ft.lbf/s is 0.00771
(ii) kinetic energy being transported by the methanol in the pipe is 1.40 x 10⁻⁵ hp

b) Additional energy is dissipated into other forms. The larger part is heat energy, but also dissipated in light, sound and vibrations.

<h3>What is kinetic energy?</h3>

The ability of an object to do work by virtue of its motion.

The mass flow rate expressed as

m= 3.00 gal.mm x 1000/264.17L/gal x 0.792 kg/L x 2.20462 / 60= 0.330 lb/s

The velocity is determined by the continuity equation

u= Q/A =[ 3.00 x 35.3145/(264.17x60) ] / π (1/12)²/4

u = 1.225 ft/s

The rate of kinetic energy transport is

K.E = 1/2 x (0.330) x (1.225)² = 0.00771 ft-lb/s

Thus, the kinetic energy rate in ft.lbf/s is 0.00771

The rate of kinetic energy in hp is

K.E = 0.00771 x 1.341 x 10⁻³ /0.7376

K.E = 1.40 x 10⁻⁵ hp

The kinetic energy being transported by the methanol in the pipe is 1.40 x 10⁻⁵ hp

b) The major amount of heat energy is dissipated. The other forms of energy is light, sound and vibrations.

Learn more about kinetic energy.

brainly.com/question/12669551

#SPJ1

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Q=hA(T_{w}-T_{inf})=16.97*0.5(27-300)=-2316.4J

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v=16.96*10^{-6}m^{2}s

Pr=0.699

k=26.56*10^{-3}W/mK

A=1*0.5m^{2}

I hope this is useful for you

regards

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