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maks197457 [2]
3 years ago
12

How does a turbo charger work

Engineering
2 answers:
yKpoI14uk [10]3 years ago
8 0

Answer:

The turbocharger on a car applies a very similar principle to a piston engine. It uses the exhaust gas to drive a turbine. This spins an air compressor that pushes extra air (and oxygen) into the cylinders, allowing them to burn more fuel each second.

Explanation:

Romashka-Z-Leto [24]3 years ago
7 0

Answer:

The turbocharger on a car applies a very similar principle to a piston engine. It uses the exhaust gas to drive a turbine. This spins an air compressor that pushes extra air (and oxygen) into the cylinders, allowing them to burn more fuel each second

Explanation:

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Explain why the following scenario fails to meet the definition of a project description.
s344n2d4d5 [400]

Answer:

The youth hockey training facility

Explanation:

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3 years ago
What are some qualities of a good engineer? Explain why each characteristic is important. (2-3 sentences minimum)
natali 33 [55]
A good engineer is smart.
8 0
3 years ago
A capillary tube is immersed vertically in a water container. Knowing that water starts to evaporate when the pressure drops bel
Anuta_ua [19.1K]

Answer:

d=0.414\times 10^{-4}\ m

Explanation:

Given that

P = 4 KPa

Contact angle = 6°

Surface tension = 1 N/m

Lets assume that atmospheric pressure = 100 KPa

Lets take that density of water =1000\ kg/m^3

So the capillarity rise h

h=\dfrac{\Delta P}{\rho g}

h=\dfrac{100\times 1000-4\times 1000}{1000\times 10}

h= 9.61 m

We know that for capillarity rise h

h=\dfrac{2\sigma cos\theta }{r\rho g}

r=\dfrac{2\sigma cos\theta }{h\rho g}

r=\dfrac{2\times 1 cos4^{\circ} }{9.61\times 1000\times 10}

r=0.207\times 10^{-4}\ m

d=0.414\times 10^{-4}\ m

3 0
3 years ago
Use the APWA 5600 methodology to compute the 1/25 design discharge for the following catchment. The catchment area consists of 1
sweet [91]

Explanation:

For a given flow rate, open channel flow based design requires larger conduit sizes than those dimensioned  based on pressure flow. While it may be more expensive to build designed storm drainage systems

Based on open channel flow, this design procedure provides a margin of safety by providing  headroom in the duct to accommodate an increase in flow above the design discharge. Beneath the majority

Under normal conditions, it is recommended that the size of storm drains be based on a gravity flow to full flow criteria  or almost full. The design of the pressure flow may be justified in certain cases. As the hydraulic calculations are  performed, frequent verification of the existence of the desired flow condition should be performed.

Storm drainage systems can often alternate between pressure and open channel flow conditions from one  section to another (Federal Highway Administration, US Department of Transportation, 1996).

For gravity flow conditions, the Manning formula must be edited as described below.

ܳ ൌ

1,486

݊

ܣܴ ଶ / ଷ ܵ ଵ / ଶ

Where:

Q = Discharge, cubic feet per second

A = flow cross-sectional area, square feet

n = Manning roughness coefficient (see Table 5603-1)

ܴ ൌ

ܣ

ܲ

R = hydraulic radius, feet

S = slope in feet per foot

P = wet perimeter in feet

5 0
4 years ago
Describe the greatest power in design according to Aravena?
KiRa [710]

The greatest power in design according to Aravena is "the power of synthesis”.

Hope that helps!

8 0
2 years ago
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