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Makovka662 [10]
3 years ago
5

Which is the correctly balanced chemical equation for the reaction of KOH and H2SO4?

Chemistry
1 answer:
Ksenya-84 [330]3 years ago
5 0

Answer:

3) 2KOH + H2SO4 → K2SO4 + 2H2O

Explanation:

The balanced chemical equation for the reaction of KOH and H2SO4 is,

→ 2KOH + H2SO4 → K2SO4 + 2H2O

Hence, option (3) is the correct answer.

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Hydrazine (N2H4) emits a large quantity of
azamat

Answer:

              1.75 moles of H₂O

Solution:

The Balance Chemical Equation is as follow,

                                   N₂H₄  +  O₂    →    N₂  +  2 H₂O

Step 1: Calculate the Limiting Reagent,

According to Balance equation,

             32.04 g (1 mol) N₂H₄ reacts with  =  32 g (1 mol) of O₂

So,

                   28 g of N₂H₄ will react with  =  X g of O₂

Solving for X,

                       X  =  (28 g × 32 g) ÷ 32.04 g

                       X  =  27.96 g of O₂

It means 29 g of N₂H₄ requires 47.96 g of O₂, while we are provided with 73 g of O₂ which is in excess. Therefore, N₂H₄ is the limiting reagent and will control the yield of products.

Step 2: Calculate moles of Water produced,

According to equation,

            32.04 g (1 mol) of N₂H₄ produces  =  2 moles of H₂O

So,

                        28 g of N₂H₄ will produce  =  X moles of H₂O

Solving for X,

                      X  =  (28 g × 2 mol) ÷ 32.04 g

                      X  =  1.75 moles of H₂O

5 0
4 years ago
What is the mass of a sample of nitrogen trichloride containing 5,500 molecules?
quester [9]
The answer is A
explanation
7 0
2 years ago
Describe 3 properties of a frozen fruit far including state of matter
miv72 [106K]
Nucleic Acids, Protein Coat,and Lipid Membrane

4 0
3 years ago
A person's temperature is 40° C. What would it be in Kelvin?
Jobisdone [24]
What do you mean.....kelvin?
3 0
3 years ago
Read 2 more answers
Suppose a thin sheet of zinc containing 0.2 mol of the metal is completely converted in air to zinc oxide (zno) in one month. ho
hram777 [196]
Molecular mass of  Zn = 65.38  
<span>1 mol = 65 g </span>
<span>0.2 mol of Zinc = 13.076 g of Zinc </span>

<span>13.076 g of Zinc is completely converted in air to ZnO </span><span>in one month
= 13.076 g / 30 days = 0.435 g per day 
</span>
<span>The rate of conversion of the zinc = 0.44 g / day</span>
8 0
3 years ago
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