Explanation:
Reversible reactions that happen in a closed system eventually reach equilibrium. At equilibrium, the concentrations of reactants and products do not change. But the forward and reverse reactions have not stopped - they are still going on, and at the same rate as each other.
The way a lack of water could affect cell functions is that cell membranes would lack structure.
Osmosis causes water to flow from the cell into the surrounding liquid. This causes the protoplasm all the material inside the cell, to shrink from the cell wall. Excessive water loss leading to cell wall breakdown can lead to cell death. Water is an important part of the protoplasm of living cells as it is directly involved in myriad biochemical reactions such as photosynthesis and respiration.
Without them, cells cannot move waste and byproducts absorb nutrients, carry out intracellular transport functions or send signals. Regulates body temperature. Moisten eye nose and mouth tissues. Protects body organs and tissues. Carry nutrients and oxygen to cells. Plasmolysis is a situation in which cells lose water in hypertonic solutions. the plant cells lose water causing them to shrink or shrink removing the cell cytoplasm from the cell wall.
Learn more about Cell functions here:-brainly.com/question/13880600
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The answer for the following problem is described below.
<em><u> Therefore the standard enthalpy of combustion is -2800 kJ</u></em>
Explanation:
Given:
enthalpy of combustion of glucose(Δ
of 
) =-1275.0
enthalpy of combustion of oxygen(Δ of 
) = zero
enthalpy of combustion of carbon dioxide(Δ of 
) = -393.5
enthalpy of combustion of water(Δ of 
) = -285.8
To solve :
standard enthalpy of combustion
We know;
Δ = ∈Δ (products) - ∈Δ (reactants)
(s) +6 (g) → 6 (g)+ 6 (l)
Δ = [6 (-393.5) + 6(-285.8)] - [6 (0) + (-1275)]
Δ = [6 (-393.5) + 6(-285.8)] - [0 - 1275]
Δ = 6 (-393.5) + 6(-285.8) - 0 + 1275
Δ = -2361 - 1714 - 0 + 1275
Δ =-2800 kJ
<em><u> Therefore the standard enthalpy of combustion is -2800 kJ</u></em>
Answer:
what the acctual fhuck typa chinese algorithim is dis, youve got me bamboozled frffr
Explanation:
jk jk.........
__5___SiO2 + ___2___CaC2 → __5___Si + ____2___CaO + __4___CO2
Answer:
The weight of the Astroturf is 179,684.31 Newtons.
Explanation:
Length of a soccer field = 0.06214 mile = 328.0992 feet
(1 mile = 5280 feet)
Breadth of a soccer field = 253 feet
Length of a Astroturf which soccer field is to be covered, l = 328.0992 feet
Breadth of a Astroturf which soccer field is to be covered ,b = 253 feet
Thickness of a Astroturf with which soccer field is to be covered = h
h = ½ inch = 0.5 inch = 0.041665 feet
(1 inches = 0.08333 feet)
Volume of the Astroturf ,V= l × b × h
Mass of the Astroturf = m
Density of the Astroturf = d = 187 
1 oz = 0.0283495 kg
Weight of the Astroturf = W
W = mg
The weight of the Astroturf is 179,684.31 Newtons.
