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Ilya [14]
1 year ago
14

Solve this system of equations by

Mathematics
2 answers:
timofeeve [1]1 year ago
8 0

Answer:

(12 , -8)

Step-by-step explanation:

<h2>Solving system of equation:</h2><h3>    Elimination method</h3>

                x + y = 4 ---------------(I)

              4x + 3y = 24 ---------------------(II)

Multiply equation (I) by (-4) and then add the equations. By doing this, 'x' will be eliminated and we can find the value of 'y'.

(I) *(-4)           -4x - 4y = -16

(II)                <u>   4x + 3y = 24 </u>   {Now add}

                             -y   = 8

                              y   = 8/(-1)

         \boxed{y = -8}

Plugin y =-8 in any of the equations. Here , we are going to plugin  equation (I)

        x + (-8) = 4

            x - 8 = 4

                  x = 4 + 8

           \boxed{x = 12}

Goshia [24]1 year ago
6 0
Answer: x = 12 and y = -8

Explanation:
x + y = 4
4x + 3y = 24
———————
-3(x + y = 4)
4x + 3y = 24
———————-
-3x - 3y = -12
4x + 3y = 24
———————
x = 12

If x = 12
x + y = 4
12 + y = 4
y = -8
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C: A line travelling to the right with an open dot on p = -3.

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What is the solution of the equation when solved using the quadratic formula?<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B
Artemon [7]

Answer:

x=\pm2i\sqrt{5}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Standard Form: ax² + bx + c = 0
  • Quadratic Formula: x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}

<u>Algebra II</u>

  • Imaginary Numbers: √-1  = i

Step-by-step explanation:

<u>Step 1: Define Equation</u>

x² + 20 = 0

<u>Step 2: Identify Variables</u>

a = 1

b = 0

c = 20

<u>Step 3: Find roots </u><em><u>x</u></em>

  1. Substitute:                    x=\frac{-0\pm\sqrt{0^2-4(1)(20)} }{2(1)}
  2. Exponents:                   x=\frac{-0\pm\sqrt{0-4(1)(20)} }{2(1)}
  3. Multiply:                        x=\frac{-0\pm\sqrt{0-80} }{2}
  4. Subtract:                       x=\frac{\pm\sqrt{-80} }{2}
  5. Factor:                          x=\frac{\pm\sqrt{-1} \sqrt{80} }{2}
  6. Simplify:                        x=\frac{\pm4i\sqrt{5} }{2}
  7. Divide:                          x=\pm2i\sqrt{5}
6 0
2 years ago
First question. The midpoint of SR is...
Blizzard [7]

The formula of a midpoint SR:

M\left(\dfrac{x_S+x_R}{2},\ \dfrac{y_S+y_R}{2}\right)

We have

S(4, 1) and M(7, -5)

Substitute:

\dfrac{4+x_R}{2}=7\qquad|\cdot2\\\\4+x_R=14\qquad|-4\\\\x_R=10\\\\\dfrac{1+y_R}{2}=-5\qquad|\cdot2\\\\1+y_R=-10\qquad|-1\\\\y_R=-11

<h3>Answer: R(10, -11)</h3>
6 0
3 years ago
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