Step-by-step explanation:
The gender of a child which is either a boy or a girl is determined by the XX-chromosomes, or XY-chromosomes.
Since the couple plan to have 5 children, the chance of a child being a boy is equal to the chance of it being a girl - the chances are 50/50.
What we do to achieve our aim is to run a simulation that would add an X or Y to an X for all 5 children.
Doing this 125 times, we obtain the number of trials we desire.
For each trial, we get for each child, C:
C1: X + (X or Y)
C2: X + (X or Y)
C3: X + (X or Y)
C4: X + (X or Y)
C5: X + (X or Y)
Since the chance of having an X is equal to the chance of having a Y, they equal probability, which is 0.5 for each.
Multiplying both sides of <span>−1/3x≤−6 by -3 results in "x is equal to or greater than 18."
Note that multiplying such an inequality requires reversing the direction of the inequality symbol.
I subst. 18 for x in </span><span>−1/3x≤−6 as a check, and found that the resulting inequality is true.</span>
36×3/4
we will simplify it in four's table
9×3=27