Answer:
D
Step-by-step explanation:
When a polynomial f(x) is divided by (x - a) then remainder is f(a)
A
divided by (x + 4 ), then a = - 4
- 8(- 4)² + 16 = 256 - 128 + 16 = 144 ≠ 20
B
divided by (x - 2), then a = 2
3(2)³ + 7(2)² + 5(2) + 2
= 3(8) + 7(4) + 10 + 2
= 24 + 28 + 12 = = 64 ≠ 20
C
divided by (x + 5) , then a = - 5
(- 5)³ + 5(- 5)² - 4(- 5) + 6
= - 125 + 125 + 20 + 6 = 26 ≠ 20
D
divided by (x - 2), then a = 2
3
- 5(2)³ + 5(2) + 2
= 3(16) - 5(8) + 10 + 2
= 48 - 40 + 12 = 20 ← Remainder of 20
<em> a₁ is the first term, d is the difference, and n is the term</em>
a₁ = -5
d = -5

<em>explicit formula</em>
<em>recursive formula</em>
Answer:
2460
Step-by-step explanation:
Hope this helps :)
Answer:
<h2>-8</h2>
Step-by-step explanation:
![4-3[6-2(4-3)]\\\\Follow\:the\:PEMDAS\:order\:of\:operations\\\\\mathrm{Calculate\:within\:parentheses}\:\left[6-2\left(4-3\right)\right] : 4\\\\=4-3\times\:4\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:3\times\:4\::\quad 12\\=4-12\\\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:4-12\:\\\\:\quad -8](https://tex.z-dn.net/?f=4-3%5B6-2%284-3%29%5D%5C%5C%5C%5CFollow%5C%3Athe%5C%3APEMDAS%5C%3Aorder%5C%3Aof%5C%3Aoperations%5C%5C%5C%5C%5Cmathrm%7BCalculate%5C%3Awithin%5C%3Aparentheses%7D%5C%3A%5Cleft%5B6-2%5Cleft%284-3%5Cright%29%5Cright%5D%20%3A%204%5C%5C%5C%5C%3D4-3%5Ctimes%5C%3A4%5C%5C%5C%5C%5Cmathrm%7BMultiply%5C%3Aand%5C%3Adivide%5C%3A%5Cleft%28left%5C%3Ato%5C%3Aright%5Cright%29%7D%5C%3A3%5Ctimes%5C%3A4%5C%3A%3A%5Cquad%2012%5C%5C%3D4-12%5C%5C%5C%5C%5Cmathrm%7BAdd%5C%3Aand%5C%3Asubtract%5C%3A%5Cleft%28left%5C%3Ato%5C%3Aright%5Cright%29%7D%5C%3A4-12%5C%3A%5C%5C%5C%5C%3A%5Cquad%20-8)
Answer:
hi
Step-by-step explanation:
hi