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Sergio039 [100]
2 years ago
11

Need an answer for expand and simplify bracket quickly please

20%2B%204%29" id="TexFormula1" title=" - 2(p - 4)(p + 4)" alt=" - 2(p - 4)(p + 4)" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
34kurt2 years ago
8 0

Answer:

-p^2+32

Step-by-step explanation:

Start by expanding the -2 into the (p-4) bracket using the distributive method:

-2(p-4)\\-2p + 8

Now, expand the result into the remaining bracket:

(-2p + 8)(p+4)\\-2p^2 -8p+8p+32\\-2p^2 + 32

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What is the product?
konstantin123 [22]

Answer:

-108

Literally just put what you wrote in the calculator

Step-by-step explanation:

4 • (-9) • (-3) • (-1)

5 0
3 years ago
How to find the maximum height projectile motion?
ziro4ka [17]
Y=v(initial)*t+1/2at^2
since the velocity is zero at the maximum height then we get
y=1/2at^2
a is just acceleration due to gravity so a=g which is 9.8 m/s^2.
so y=1/2gt^2.
7 0
3 years ago
If 5x – 4 = 31, what is the value of x?​
Lunna [17]

Answer:

x = 5 \frac{2}{5}

Step-by-step explanation:

Hi there!

So, to answer this problem, I'll use the reverse method.

31 - 4 = 27,

So how many times, can 5 go into 27?

The closest factor of 5 to 27 is 25.

5 can go in to 27,  5 times.

Continuing on, there is a 2 left over, so the answer to your question is

x = 5 \frac{2}{5}

5 · 5 \frac{2}{5} - 4 = 31

Let me know if I am incorrect and I will attempt to find the right answer for you.

<em>waffletowne</em>

7 0
2 years ago
Read 2 more answers
A feasible region has vertices at (-1,3), (3,5), (4,-1), and (-1,-2) find the maximum and minimum values of each function
Molodets [167]
Answer: Choice D. 
Max: f (-1,-2)=4; min:f(3,5)=-11

----------------------------------------
----------------------------------------

Work Shown:

Plug in (x,y) = (-1,3)
f(x,y) = -2x-y
f(-1,3) = -2*(-1)-3
f(-1,3) = 2-3
f(-1,3) = -1
------------------
Plug in (x,y) = (3,5)
f(x,y) = -2x-y
f(3,5) = -2*3-5
f(3,5) = -6-5
f(3,5) = -11
------------------
Plug in (x,y) = (4,-1)
f(x,y) = -2x-y
f(4,-1) = -2*4-(-1)
f(4,-1) = -8+1
f(4,-1) = -7
------------------
Plug in (x,y) = (-1,-2)
f(x,y) = -2x-y
f(-1,-2) = -2*(-1)-(-2)
f(-1,-2) = 2+2
f(-1,-2) = 4
------------------
The four outputs are: -1, -11, -7, and 4

The largest output is 4 and that happens when (x,y) = (-1,-2)
So the max is f(x,y) = 4

The smallest output is -11 and that happens when (x,y) = (3,5)
So the min is f(x,y) = -11

This all points to choice D being the answer.

6 0
3 years ago
One positive number is the square of another positive number. their sum is 132. find the numbers.
Jet001 [13]
X +x²= 132
x +x²-132= 132-132
x²+x -132 = 0
(x-11) (x+12) = 0
x-11 = 0 X+12=0
x-11+11 = 0+11 X+12-12=0-12
x =11 x= -12

Check
x +x²= 132 x +x²= 132
-12 +-12²= 132 11 +11²= 132
-12 + 144 = 132 11+ 121=132
132= 132 132=132

Since the problem says positive the answer is (11,121)
8 0
3 years ago
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