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Gwar [14]
3 years ago
5

What type of dilation occurs with a scale factor of 3/2?

Mathematics
1 answer:
pickupchik [31]3 years ago
8 0

Answer:

A figure is reflected in two intersecting lines that form an angle of 40°

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Let U={1,2,3,4,5,6,7,8}A={2,3,6}B={2,4,5,7}C={1,7,8}Find the following use the roster method to write method to write the set. E
Ipatiy [6.2K]

A U B = set of all elements that are in both A or B:

A U B = {2, 3, 4, 5, 6, 7}

Here is a picture to see our answer.

6 0
1 year ago
PLEASE HELP ASAP!!!!!!!
vlada-n [284]

Answer:

  A.) the SSS Postulate

Step-by-step explanation:

Two sides of each triangle are marked congruent, and the third side is shared by the triangles. Hence, all three sides are congruent, and the SSS Postulate applies.

4 0
3 years ago
$140 for 18ft squared=?????
andrew11 [14]
Unit rate means how much does it cost for 1 unit
140 for 18ft^2

divide by 18
140/18=7.77777777777777
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8 0
3 years ago
Read 2 more answers
Solve the equation for t. (t-7)^2+18=9
Anika [276]

Answer:

t = 7 + 3i

Step-by-step explanation:

(t-7)^2 + 18 = 9

(t-7)^2 = 9 - 18

(t-7)^2 = -9

(t-7) = sqrt(-9) = |3| sqrt(-1)

t = 7 + 3i

4 0
2 years ago
1. Let L be a list of numbers in non-decreasing order, and x be a given number. Describe an algorithm that counts the number of
e-lub [12.9K]

Answer:

Algorithm

Start

Int n // To represent the number of array

Input n

Int countsearch = 0

float search

Float [] numbers // To represent an array of non decreasing number

// Input array elements but first Initialise a counter element

Int count = 0, digit

Do

// Check if element to be inserted is the first element

If(count == 0) Then

Input numbers[count]

Else

lbl: Input digit

If(digit > numbers[count-1]) then

numbers[count] = digit

Else

Output "Number must be greater than the previous number"

Goto lbl

Endif

Endif

count = count + 1

While(count<n)

count = 0

// Input element to count

input search

// Begin searching and counting

Do

if(numbers [count] == search)

countsearch = countsearch+1;

End if

While (count < n)

Output count

Program to illustrate the above

// Written in C++

// Comments are used for explanatory purpose

#include<iostream>

using namespace std;

int main()

{

// Variable declaration

float [] numbers;

int n, count;

float num, searchdigit;

cout<<"Number of array elements: ";

cin>> n;

// Enter array element

for(int I = 0; I<n;I++)

{

if(I == 0)

{

cin>>numbers [0]

}

else

{

lbl: cin>>num;

if(num >= numbers [I])

{

numbers [I] = num;

}

else

{

goto lbl;

}

}

// Search for a particular number

int search;

cin>>searchdigit;

for(int I = 0; I<n; I++)

{

if(numbers[I] == searchdigit

search++

}

}

// Print result

cout<<search;

return 0;

}

8 0
3 years ago
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