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3 years ago

What type of dilation occurs with a scale factor of 3/2?

Mathematics

1 answer:

pickupchik [31]3 years ago

8 0

Answer:

A figure is reflected in two intersecting lines that form an angle of 40°

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IM having a bad day help pleaseeeee

Lisa [10]

Answer:

"i forgot"

Step-by-step explanation:

6 0

3 years ago

choose the point-slope form and f the equation below that represents the line through the point (6,-3) and has a slope of 1/2

AveGali [126]

Answer:

The point-slope form of this equation would be y + 3 = 1/2(x - 6)

Step-by-step explanation:

In order to find this, start with the base form of point-slope form.

y - y1 = m(x - x1)

Now input the slope for m and the point for (x1, y1)

y - -3 = 1/2(x - 6)

y + 3 = 1/2(x - 6)

6 0

3 years ago

Read 2 more answers

in exercises 15-20 find the vector component of u along a and the vecomponent of u orthogonal to a u=(2,1,1,2) a=(4,-4,2,-2)

Nimfa-mama [501]

Answer:

The component of $\vec u$ orthogonal to $\vec a$ is $\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$ .

Step-by-step explanation:

Let $\vec u$ and $\vec a$ , from Linear Algebra we get that component of $\vec u$ parallel to $\vec a$ by using this formula:

$\vec u_{\parallel \,\vec a} = \frac{\vec u \bullet\vec a}{\|\vec a\|^{2}} \cdot \vec a$ (Eq. 1)

Where $\|\vec a\|$ is the norm of $\vec a$ , which is equal to $\|\vec a\| = \sqrt{\vec a\bullet \vec a}$ . (Eq. 2)

If we know that $\vec u =(2,1,1,2)$ and $\vec a=(4,-4,2,-2)$ , then we get that vector component of $\vec u$ parallel to $\vec a$ is:

$\vec u_{\parallel\,\vec a} = \left[\frac{(2)\cdot (4)+(1)\cdot (-4)+(1)\cdot (2)+(2)\cdot (-2)}{4^{2}+(-4)^{2}+2^{2}+(-2)^{2}} \right]\cdot (4,-4,2,-2)$

$\vec u_{\parallel\,\vec a} =\frac{1}{20}\cdot (4,-4,2,-2)$

$\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$

Lastly, we find the vector component of $\vec u$ orthogonal to $\vec a$ by applying this vector sum identity:

$\vec u_{\perp\,\vec a} = \vec u - \vec u_{\parallel\,\vec a}$ (Eq. 3)

If we get that $\vec u =(2,1,1,2)$ and $\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$ , the vector component of $\vec u$ is:

$\vec u_{\perp\,\vec a} = (2,1,1,2)-\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$

$\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$

The component of $\vec u$ orthogonal to $\vec a$ is $\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$ .

4 0

3 years ago

(100 POINTS) Amanda, Lisa, and Raquel together sold 54 tickets for the school play. Amanda sold 22 tickets and Lisa sold 14 tick

stepan [7]

Question 1. Raquel sold 18 tickets since if you do 54-22-14 you would get 18

(c)

6 0

2 years ago

Read 2 more answers

What is the length, in meters, of the ramp, line segment AC, below? Round to the nearest whole number if necessary.

Brrunno [24]

10 meters.

Step-by-step explanation:

To find the missing side of a right triangle, we can use the Pythagorean theorem.

The Pythagorean theorem is...

$a^2+b^2=c^2$

Please be sure to note that a and b will always be the length of the sides and c will always be the hypotenuse, or in this case the ramp.

Since we know the values of both of the sides we can plug this into the theorem.

$6^2+8^2=c^2$

Now we can solve.

$36+64+c^2$

Add.

$100=c^2$

Many people will make the mistake of thinking 100 is the final answer, but since c is squared we need to find the square root of 100.

$\sqrt{100} =10$

c = 10

The ramp is 10 meters.

6 0

3 years ago

What type of dilation occurs with a scale factor of 3/2￼?

What type of dilation occurs with a scale factor of 3/2?