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2 years ago

Which expression is equivalent to 11x + 5 + 2x - 3? (HINT: Combine LIKE TERMS)

Mathematics

2 answers:

natulia [17]2 years ago

5 0

Answer:

4.13x+2

Step-by-step explanation:

11x+5+2x-3

13x+5-3

13x+2

goldfiish [28.3K]2 years ago

4 0

Answer:

4 .13x+2

<h2>and don't ever try to copy and this app is for homework but other tests </h2>

hope you understand

pls take it positively

and I hope you will not do this for next test

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2 Points

pav-90 [236]

Subtract 15 from both sides.
28-15=13
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3 years ago

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Rom4ik [11]

I’m not sure but is it C?

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1 year ago

An equation with no solutions 3x + 7 = X + 3

max2010maxim [7]

Answer:

X = -2

Step-by-step explanation:

Hope this helps

7 0

2 years ago

Describe the solutions of 2-5>n in words

inna [77]

$2-5\ \textgreater \ n \ \textgreater \ Switch\;sides \ \textgreater \ n\ \textless \ 2-5 \ \textgreater \ Simplify \ \textgreater \ 2-5 \ \textgreater \ -3$

$n\ \textless \ -3$

Hope this helps!

5 0

3 years ago

Write an equation for the hyperbola with vertices (-7,0) and (7,0), conjugate axis of length of 10?

lina2011 [118]

The hyperbola is more or less as in the picture below

notice the traverse axis is horizontal, meaning the positive fraction will be the one with the "x" variable in it, and notice the length of the "a" component

the conjugate axis is 10, notice the length of the "b" component

thus $\bf \textit{hyperbola with horizontal traverse axis }\\\\
\cfrac{(x-{{ h}})^2}{{{ a}}^2}-\cfrac{(y-{{ k}})^2}{{{ b}}^2}=1
\qquad center\ ({{ h}},{{ k}})\qquad
 vertices\ ({{ h}}\pm a, {{ k}})$

so, hmmmm plug in those values

6 0

2 years ago