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aleksandr82 [10.1K]

2 years ago

7

A 480 g falcon reaches a speed of 75 m/s in a vertical dive. if we assume that the falcon speeds up under the influence of gravi

ty only, what is the minimum height of the dive needed (ignore air friction) in meters.

1 answer:

poizon [28]2 years ago

8 0

Answer:

286.7 m

Explanation:

So we are assuming the PE of the falcon is converted to KE

KE = PE

1/2 (.480)(75)^2 = .480 (9.81)(h ) solve for h = 286.7 m

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You are a pirate working for dread pirate roberts. you are in charge of a cannon that exerts a force 20000 n on a cannon ball wh

Crazy boy [7]

Refer to the diagram shown below.

F = 2000 N, the force exerted on the cannonball
L = 2.41 m, the length of the barrel
V₀ = 83 m/s, the launch velocity
θ = 35°, the launch angle

Let m = the mass of the cannonball.
Let a = the acceleration of the ball when fired.

The net force acting on the ball is
F - mg sinθ = 2000 - 9.8*m*sin(35°) = 2000 - 5.621*m N

Then, from Newton's Law of motion,
F = ma
2000 - 5.621*m = m*a (1)

The launch velocity is V₀ = 8.3 m/s, therefore
V₀² = 2*a*L
(83 m/s)² = 2*(a m/s²)*(2.41 m)
6889 = 4.82*a
a = 6889/4.82 = 1429.25 m/s² (2)

Insert (2) into (1)
2000 - 5.621*m = 1429.25*m
2000 = 1434.871*m
m = 1.394 kg

Answer: 1.394 kg

4 0

4 years ago

Which of the following is NOT NECESSARILY a property of an air mass?

lilavasa [31]

Answer:

a.

Explanation:

a

The property of air mass include

1) it must be large.

2) it must have relatively uniform properties.

3)it must travel as a recognizable entity.

It must have a warm front at its leading edge, is not necessarily a property of an air mass because Not all air masses have a warm front at their leading edge. There are five types of air masses and different types of the front can be developed.

4 0

4 years ago

In a double-slit experiment, the second-order bright fringe is observed at an angle of 0.61°. If the slit separation is 0.11 mm,

tankabanditka [31]

Answer:

$5.86\times 10^{-7}\ \text{m}$

Explanation:

d = Slit separation = 0.11 mm

$\theta$ = Angle = $0.61^{\circ}$

m = Order = 2

$\lambda$ = Wavelength

We have the relation

$d\sin\theta=m\lambda\\\Rightarrow \lambda=\dfrac{d\sin\theta}{m}\\\Rightarrow \lambda=\dfrac{0.11\times 10^{-3}\times \sin0.61^{\circ}}{2}\\\Rightarrow \lambda=5.86\times 10^{-7}\ \text{m}$

The wavelength of the light is $5.86\times 10^{-7}\ \text{m}$ .

8 0

3 years ago

Can yall do this for me??

Sonbull [250]

Answer:

just want points

Explanation:

dont know want points

3 0

3 years ago

Let us suppose the magnitude of the original Coulomb force between the two charged spheres is FF. In this scenario, a third sphe

Vinil7 [7]

Answer:

F ’= 1/32 F

We see that the value of the force is the initial force over 32

Explanation:

In this problem the sphere that is touching the others is connected to ground, after each touch,

Let's analyze the charge of the gray sphere, when you touch it for the first time, the charge is divided between the two spheres each having Q / 2, when the sphere separates and touches ground, its charge passes zero. When I touch the gray dial again, its charge is reduced by half

½ (Q / 2) = ¼ Q

For the red dial repeat the same scheme

with the first touch the charge is reduced to Q / 2

with the second touch e reduce to ½ (Q / 2) = ¼ Q

with the third toce it is reduced to ½ (¼ Q) = ⅛ Q

Now let's analyze what happens to the electric force

if the force is F for when the charge of each sphere is Q

F = k Q Q / r²

with the remaining charge strength is

F ’= k (¼ Q) (⅛ Q) / r²

F ’= 1/32 k Q Q / r²

F ’= 1/32 F

We see that the value of the force is the initial force over 32

6 0

3 years ago