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aleksandr82 [10.1K]
2 years ago
7

A 480 g falcon reaches a speed of 75 m/s in a vertical dive. if we assume that the falcon speeds up under the influence of gravi

ty only, what is the minimum height of the dive needed (ignore air friction) in meters.
Physics
1 answer:
poizon [28]2 years ago
8 0

Answer:

286.7 m

Explanation:

So we are assuming the PE of the falcon is converted to KE

KE = PE

1/2 (.480)(75)^2 = .480 (9.81)(h )    solve for h = 286.7 m

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kondor19780726 [428]

Answer:

1. b

2. c

3. b

4. a

5. a

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7. c

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7 0
3 years ago
A simple model for a person running the 100 m dash is to assume the sprinter runs with constant acceleration until reaching top
Trava [24]

Answer:

He will complete the race in total time of T = 10 s

Explanation:

Total distance moved by the sprinter in 2.14 s is given as

s = \frac{(v_{in} + v_{f})}{2} time

s = \frac{(0 + 11.2)}{2} (2.14)

s = 11.98 m

now the distance remaining to move

d = 100 - 11.98 = 88 m

now he will move with uniform maximum speed for the remaining distance

so we will have

time = \frac{d}{v}

time = \frac{88}{11.2} = 7.86 s

so the total time to complete the race is given as

T = 7.86 + 2.14 = 10 s

6 0
3 years ago
12. A rocket, initially at rest on the ground, accelerates vertically. It accelerates uniformly until it
vodomira [7]

Answer:

We kindly invite you to read carefully the explanation and check the image attached below.

Explanation:

According to this problem, the rocket is accelerated uniformly due to thrust during 30 seconds and after that is decelerated due to gravity. The velocity as function of initial velocity, acceleration and time is:

v_{f} = v_{o}+a\cdot (t-t_{o}) (1)

Where:

v_{o} - Initial velocity, measured in meters per second.

v_{f} - Final velocity, measured in meters per second.

a - Acceleration, measured in meters per square second.

t_{o} - Initial time, measured in seconds.

t - Final time, measured in seconds.

Now we obtain the kinematic equations for thrust and free fall stages:

Thrust (v_{o} = 0\,\frac{m}{s}, a = 30\,\frac{m}{s^{2}}, t_{o} = 0\,s, 0\,s\le t< 30\,s)

v = 30\cdot t (2)

Free fall (v_{o} = 900\,\frac{m}{s}, a = -9.807\,\frac{m}{s}, t_{o} = 30\,s, 30\,s \le t \le 120\,s)

v = 900-9.81\cdot (t-30) (3)

Now we created the graph speed-time, which can be seen below.

5 0
3 years ago
DEFINE REFRACTION? describe how a ray of light is refracted when it passes through a glass block​
jek_recluse [69]
When a ray passes from air into glass the direction in which the light ray is travelling changes. The light ray appears to bend as it as it passes through the surface of the glass. ... This 'bending of a ray of light' when it passes from one substance into another substance is called refraction.
8 0
3 years ago
Orlat
Nana76 [90]

The maximum force that the athlete exerts on the bag is equal to 1,500 N and in the opposite direction as the force that the bag exerts on the athlete.

<h3>Newton's third law of motion</h3>

Newton's third law of motion states that action and reaction are equal and opposite.

Fa = -Fb

The force exerted by the athlete on the bag is equal to the force the bag exerted on the athlete but in opposite direction.

Thus, the maximum force that the athlete exerts on the bag is equal to 1,500 newtons and in the opposite direction as the force that the bag exerts on the athlete.

Learn more about force here: brainly.com/question/12970081

#SPJ1

8 0
3 years ago
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