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3 years ago

10

In a double-slit experiment, the second-order bright fringe is observed at an angle of 0.61°. If the slit separation is 0.11 mm,

then what is the wavelength of the light?

1 answer:

tankabanditka [31]3 years ago

8 0

Answer:

$5.86\times 10^{-7}\ \text{m}$

Explanation:

d = Slit separation = 0.11 mm

$\theta$ = Angle = $0.61^{\circ}$

m = Order = 2

$\lambda$ = Wavelength

We have the relation

$d\sin\theta=m\lambda\\\Rightarrow \lambda=\dfrac{d\sin\theta}{m}\\\Rightarrow \lambda=\dfrac{0.11\times 10^{-3}\times \sin0.61^{\circ}}{2}\\\Rightarrow \lambda=5.86\times 10^{-7}\ \text{m}$

The wavelength of the light is $5.86\times 10^{-7}\ \text{m}$ .

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A thin ring of radius R is uniformly charged with the total positive charge Q. 1. Find the electric field at distance h right ab

Paha777 [63]

Answer:

$E_{net} = \frac{k Q h}{(R^2 + h^2)^{\frac{3}{2}}}$

Explanation:

If charge Q is uniformly distributed over the ring then for small element of the ring the charge will be given as

$dq = \frac{Q}{2\pi R} dL$

now electric field due to this small element on the axis of ring at height "h" is given as

$dE = \frac{k dq}{R^2 + h^2}$

now since this electric field is radially in the direction of joining the position of charge to the given point

so net field due to ring will be along the axis of ring

so we have

$E_{net} = \int dEcos\theta$

$E_{net} = \int \frac{k dq}{R^2 + h^2} \frac{h}{\sqrt{R^2 + h^2}}$

$E_{net} = \frac{k Q h}{(R^2 + h^2)^{\frac{3}{2}}}$

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3 years ago

True or false a self contained living thing is called adaptation

motikmotik

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2 years ago

elena-s [515]

Internal energy is B. The sum of the kinetic and potential energies of the particles in a system

Explanation:

The internal energy possessed by the particles in any substance has two origins:

Part of the energy of the particles is due to the motion of the particles. In fact, for a substance at a temperature larger than absolute zero, the particles in the substance are always in motion (for a solid, they just vibrate around their fixed position, while in a liquid and in a gas, the particles are actually free to move). Because of this motion, the particles have kinetic energy. The temperature of a substance is a measure of the average kinetic energy of the particles in the substance.
The rest of the energy of a substance is in the form of potential energy, and it refers to the energy contained in the bonds between the particles of the substance (for instance, in the intermolecular bonds between different atoms in a solid). For a gaseous substance, these intermolecular bonds are very weak, therefore the potential energy is not considered and the internal energy of a gas depends only on its kinetic energy (and therefore, only on the temperature of the substance).

Therefore, the internal energy of a substance is the sum of the kinetic and the potential energies of the particles in the substance.

Learn more about energy:

brainly.com/question/6536722

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brainly.com/question/10770261

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3 years ago

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OLEGan [10]

Answer:

C!

Explanation:

Cold fronts generally advance at average speeds of 20 to 25 mph. toward the east — faster in the winter than summer — and are usually oriented along a northeast to southwest line.

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3 years ago

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A 27.0 g marble sliding to the right at 56.8 cm/s overtakes and collides elastically with a 13.5 g marble moving in the same dir

Nataly [62]

Answer: $v_1=28.4 cm/s$

Explanation:

Given

mass of marble $m_1=27 gm$

velocity of marble $u_1=56.8 cm/s \approx 0.568 m/s$

mass of second marble $m_2=13.5 gm$

Velocity of second marble $u_2=14.2 cm/s \approx 0.142 m/s$

After collision 13.5 gm marble moves to the right at i.e. $v_2=71 cm/s$

Conserving momentum

$m_1u_1+m_2u_2=m_1v_1+m_2v_2$

$27\times 56.8+13.5\times 14.2=27\times v_1+13.5\times 71$

$1533.6+191.7=27\cdot v_1+958.5$

$27\cdot v_1=766.8$

$v_1=\frac{766.8}{27}=28.4 cm/s$

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3 years ago