Answer:
Centripetal acceleration of the car is (4.96 g) m/s²
Explanation:
It is given that,
Radius of circle, r = 95 m
Speed of the car, v = 68 m/s
We need to find the centripetal acceleration. It is given by :
So,
Since, g = 9.8 m/s²
So,
So, the magnitude of the centripetal acceleration is (4.96 g) m/s². Hence, this is the required solution.
Impulse equals Change in Momentum
F = average applied force = to be determined
Δt = time during which the force is applied = 0.50 s
m = mass = 1,700 kg
Δp = change in momentum = to be determined
Δv = change in velocity = to be determined
v1 = initial velocity = 50.0 km/h = 50,000 m/h = 13.9 m/s
v2 = final velocity = 0.00 km/h = 0.00 m/s
F∙Δt = Δp
F∙Δt = m∙Δv
F∙Δt = m∙(v2 - v1)
F = m∙(v2 - v1) / Δt
F = 1,700 kg∙(0.00 m/s - 13.9 m/s) / 0.50 s
<span>F = -47,222 N The negative sign means that the force vector is </span>
<span>applied AGAINST the momentum vector of the rhinoceros.</span>
Answer:
Work = 0.36N
Explanation:
Given
Force = 12N
Distance = 0.03m
Weight = 0.05kg
Required
Determine the work done
Workdone is calculated as thus;
Work = Force * Distance
Substitute 12N for Force and 0.03m for Distance
Work = 12N * 0.03m
Work = 0.36Nm
Using proper S.I units
Work = 0.36N
Hence, work done by the spring on the ball is 0.36N
Answer:
Explanation:
mass of coffee filter, m = 1.4 h
height, h = 4 m
velocity, v = 0.5 m/s
The energy conservation
Potential energy of filter = kinetic energy of filter + energy gained by the air molecules
m x g x h = 0.5 x mv² + energy gained by the air molecules
0.0014 x 9.8 x 4 = 0.5 x 0.0014 x 0.5 x 0.5 + Energy gained by the air molecules
Energy gained by the air molecules = 0.05488 - 0.00000175
= 0.054878 J