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2 years ago

6 cm 5 cm 4 cm 3 cm what does that equal I have done everything and I can't get it right

Mathematics

1 answer:

stiks02 [169]2 years ago

8 0

Answer:

Sum: 18

Conversion to inches: 7.0866

Step-by-step explanation:

Not exactly sure what you are trying to ask here... But I'll do my best?

1. If you are trying to add each measurement together, you start by writing out: 6 + 5 + 4 + 3. Now you can break it down into smaller parts to be easier.

6 + 5 = 11. 11 + 4 = 15. 15 + 3 = 18.

So the sum of the measurements is 18!

_________________

2. If you are trying to convert this measurement into inches, you could follow these directions:

Since one inch is equal to about 2.54 centimeters, you would need to divide the sum of the values by 2.54.

So 18 / 2.54 is roughly equal to: 7.0866.

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Which function below is the inverse of f(x)= 3x+5/7

valkas [14]

Answer:

$\huge\boxed{f^{-1}(x) = \frac{7x-5}{3}}$

Step-by-step explanation:

Given the function:

$f(x) = \frac{3x+5}{7}$

Put f(x) = y

$y = \frac{3x+5}{7}$

Interchange x and y

$x = \frac{3y+5}{7}$

Solve for y

$x = \frac{3y+5}{7}$

Multiplying both sides by 7

$7x = 3y+5$

Subtracting y to both sides

$7x-5 = 3y$

Dividing both sides by 3

$\frac{7x-5}{3} = y$

$y = \frac{7x-5}{3}$

Put y = $f^{-1}(x)$

So,

$f^{-1}(x) = \frac{7x-5}{3}$

Hope this helped!

<h2>~AnonymousHelper1807</h2>

5 0

4 years ago

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IRISSAK [1]

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4 years ago

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3 years ago

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Water use in the summer is normally distributed with a mean of 311.4 million gallons per day and a standard deviation of 40 mill

r-ruslan [8.4K]

Answer: 0.965

Step-by-step explanation:

Given : Water use in the summer is normally distributed with

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$\sigma=40 \text{ million gallons per day}$

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Z-score : $\dfrac{x-\mu}{\sigma}$

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3 years ago

Triangle WXY is isosceles. ∠YWX and ∠YXW are the base angles. YZ bisects ∠WYX. m∠XYZ = (15x)°. m∠YXZ = (2x + 5)°. What is the me

NARA [144]

Step-by-step explanation:

angle YWX = angle YXW ...eqn 1

angle XYZ = angle WYX (0.5) = 15x...eqn 2

angle YXZ = angle YXW = 2x + 5...eqn 3

=> from eqn 1 and 3 we get...

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=> from eqn 2 we get

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