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Usimov [2.4K]
2 years ago
12

What is

alt="(\frac{1}{5} )^{4}" align="absmiddle" class="latex-formula"> HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Mathematics
1 answer:
DanielleElmas [232]2 years ago
5 0

\sf{Hey!}

\boxed{\underline{Question:}}

(\frac{1}{5})^4 = \frac{1}{632}

If you want the decimal.

^A^n^s^w^e^r^~:

0.0016.

\huge\bold{\textbf{\textsf{{\color{EXPLANATION :}{}}}}}

Apply exponent rule: (\frac{a}{b})^c =\frac{a^c}{b^c}

= \frac{1^4}{5^4}

1^4=1

=\frac{1}{5^4}

5^4=625

= \frac{1}{625}

Hope It Helps. . .

Answer~:

\sf{Jace}

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625.25

Step-by-step explanation:

the answer is 625.25

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Answer:

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3 years ago
20 points!! I need help
zaharov [31]

Answer:

11.33 * 16.33 meters to the nearest hundredth.

Step-by-step explanation:

Let the width of the pool be x meters, then the length is x+5 meters.

The length of whole area = x + 5 + 2(3)  = x + 11 meters and the width is

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So we have the equation (x + 6)(x + 11) = 387.

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So the width is 11.3 m and the length is 16.33 meters.

4 0
3 years ago
Which of the following demonstrates the Commutative Property of Multiplication? 2(6a − 3) = (6a − 3) ⋅ 2 2(6a − 3) = 12a − 6 12a
omeli [17]

Answer:

<h2>A</h2>

Step-by-step explanation:

The Commutative Property of Multiplication states that it doesn't matter in what order you multiply terms to get the same answer:

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3 years ago
Sec squared 55 - tan squared 55
sergejj [24]

<u>Answer: </u>

sec squared 55 – tan squared 55  = 1

<u>Explanation:</u>

Given, sec square 55 – tan squared 55

We know that,

\sec \Theta=\frac{\text {hypotenuse}}{\text {base}}

And,

\tan \theta=\frac{\text { perpendicular }}{\text { base }}

where Ө is the angle

Substituting the values

\left(\frac{\text {hypotenuse}}{\text {base}}\right)^{2}-\left(\frac{\text { perpendicular }}{\text {base}}\right)^{2}

Solving,

\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}

According to Pythagoras theorem,

\text { (hypotenuse) }^{2}-\text { (perpendicular) }^{2}=(\text { base })^{2}

Putting this in the equation;

squared 55 - tan squared 55 =

\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}=\frac{(\text {base})^{2}}{(\text {base}) *(\text {base})}=1

Therefore, sec squared 55 – tan squared 55 = 1

6 0
3 years ago
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