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son4ous [18]
2 years ago
14

Find the exact value of tan(x-y) if sin x=8/17 cosy = 3/5

Mathematics
1 answer:
jolli1 [7]2 years ago
6 0

To solve the the question we proceed as follows:

From trigonometric laws

(cos x)^2+(sin x)^2=1

(cos x)^2+(sin x)^2=1

sin (x-y)=sin x sin y-sin y cos x

cos (x-y)=cos x cos y+sin x xin y

si  x=\frac{8}{17}

cos x=sqrt(1-(sin x)^2)=sqrt(1-64/289)=sqrt(\frac{225}{289} )=\frac{15}{17}

cos y=\frac{3}{5}

sin x= sqrt(1- (cos x)^2)= sqrt(1-\frac{9}{25} )=sqrt(\frac{16}{25} )=\frac{4}{5}

thus

tan (x-y)=[sin (x-y)]/[cos (x-y)]

=[sin x cos y-sin y cos x]/[cos x cos y+sin x sin y]

plugging in the values we obtain:

[8/17 *3/5-4/5*15/7]/[15/17*3/5+8/17*4/5]

simplifying

[24/85-60/85]/[45/85+32/85]

=-\frac{36}{77}

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30 points!<br>please help<br><br>in return brainliest and special thanks
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22. Distributive Property
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3) Veronica traveled 126 miles on 3 gallons of gas. On another trip she traveled 210 miles on 5 gallons of gas. Find the unit ra
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The answer is 42 mpg, all you need to do is divide 126/3 or 210/5 and they both equal 42.
8 0
3 years ago
1. JP Construction is building a rectangular children's wading pool for the local community center. The pool will be 4.5 meters
Bond [772]

Answer:

x\leq 1.78

Step-by-step explanation:

We are given that

Width of pool, b=4.5 m

We have to find the inequality which  represents the possible lengths of the wading pool.

Let x be the length of wading pool

We know that

Area of rectangle=length\times breadth

According to question

Using the formula

4.5x\leq 8

Divide by 4.5 on both sides we get

x\leq\frac{8}{4.5}

x\leq 1.78

5 0
3 years ago
Write the equation of a polynomial of degree 3, with zeros 1, 2 and -1 where f(0)=2
drek231 [11]

<u>Answer:</u>

The equation of a polynomial of degree 3, with zeros 1, 2 and -1 is x^{3}-2 x^{2}-x+2=0

<u>Solution:</u>

Given, the polynomial has degree 3 and roots as 1, 2, and -1. And f(0) = 2.

We have to find the equation of the above polynomial.

We know that, general equation of 3rd degree polynomial is  

F(x)=x^{3}-(a+b+c) x^{2}+(a b+b c+a c) x-a b c=0

where a, b, c are roots of the polynomial.

Here in our problem, a = 1, b = 2, c = -1.

Substitute the above values in f(x)

F(x)=x^{3}-(1+2+(-1)) x^{2}+(1 \times 2+2(-1)+1(-1)) x-1 \times 2 \times(-1)=0

\begin{array}{l}{\rightarrow x^{3}-(3-1) x^{2}+(2-2-1) x-(-2)=0} \\ {\rightarrow x^{3}-(2) x^{2}+(-1) x-(-2)=0} \\ {\rightarrow x^{3}-2 x^{2}-x+2=0}\end{array}

So, the equation is x^{3}-2 x^{2}-x+2=0

Let us put x = 0 in f(x) to check whether our answer is correct or not.

\mathrm{F}(0) \rightarrow 0^{3}-2(0)^{2}-0+2=2

Hence, the equation of the polynomial is x^{3}-2 x^{2}-x+2=0

3 0
3 years ago
QUESTION 29
Shalnov [3]

The sum of the set of x - values given to us is calculated as; ∑X = -1

<h3>How to find the the sum of a set of data?</h3>

We are given;

X1 = 2, X2 = -8, X3 = 4, X4 = -8 and Y1 = -3, Y2 = -8, Y3 = 10, Y4 = 6

1) ∑X = X1 + X2 + X3 + X4

∑X = 2 + (-8) + 4 + 1 = -1

2) ∑Y = Y1 + Y2 + Y3 + Y4

∑Y = 3 + (-8) + 10 + 6

∑Y = -11

3) ∑ X² = X₁² + X₂² + X₃² + X₄²

∑X² = (2)² + (-8)² + (4)² + (1)²

∑X² = 85

4) ∑Y² = Y₁² + Y₂² + Y₃² + Y₄²

∑X² = (-3)² + (-8)² + (10)² + (6)²

∑X² = 209

Complete question is;

Two variables, X and Y assume the values X1 = 2, X2 = -5, X3 = 4, X4 = 1 and Y1 = -3, Y2 = -8, Y3 = 10, Y4 = 6, respectively. Calculate (a) ∑X, (b) ∑ Y, (c) ∑ X² (d) ∑ Y²

Read more about Sum of data at; brainly.com/question/15858152

#SPJ1

6 0
2 years ago
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