There’s no image shown can u attach one
The answer is 1/64
Hope this helped you
Answer:
The answer is A
Step-by-step explanation:
Answer:
k=2
Problem:
if the equation x^2 +(k+2)x+2k=0 has equal roots,then the value of k is ..
Step-by-step explanation:
Since the coefficient of x^2 is 1, we can use this identity to aid us: x^2+bx+(b/2)^2=(x+b/2)^2.
So we want the following:
[(k+2)/2]^2=2k
Apply the power on the left:
(k+2)^2/4=2k
Multiply both sides by 4:
(k+2)^2=8k
Expand left side:
k^2+4k+4=8k *I used identity (x+c)^2=x^2+2xc+c^2
Subtract 8k on both sides:
k^2-4k+4=0
Factor using the identity mentioned a couple lines above:
(k-2)^2=0
Since zero squared is zero, we want k-2=0.
Adding both sides by 2 gives k=2.
You need to simplify it
lets start with your orgininal equation here:
-5+3x=10
Now lets try and get "x" alone. we will do this by adding 5 to both sides.
-5+3x=10
+5 +5
3x=15
Now we have 3 times "x" equals 15
The next step would be to divide both sides by 3 in order to get "x" alone.
3x=15
x=15/3
x=5
