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oksano4ka [1.4K]
2 years ago
8

We want to find the zeros of this polynomial: p(x)=5x^3-5x^2-10xp(x)=5x 3 −5x 2 −10x

Mathematics
1 answer:
butalik [34]2 years ago
7 0

Answer:

x = -1, 0, 2

Step-by-step explanation:

p(x) = 5x³ − 5x² − 10x

Factor the greatest common factor:

p(x) = 5x (x² − x − 2)

Now factor the quadratic. You can use the AC method, the quadratic formula, the rational root test, or trial and error.

p(x) = 5x (x − 2) (x + 1)

Finally, set each factor equal to 0 and solve for x.

5x = 0 → x = 0

x − 2 = 0 → x = 2

x + 1 = 0 → x = -1

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Interior and Exterior Triangle Angles (0/5)
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Answer:

<h3>      ∠R = 69</h3>

Step-by-step explanation:

<h2>Angle sum property</h2>

Sum of all angles of triangle = 180

     5x - 11 + 3x - 3 + 3x + 18 = 180

      5x + 3x + 3x  -11 - 3 + 18 = 180

Combine like terms

                             11x  + 4 = 180

                                   11x = 180 - 4

                                   11x = 176

                                      x = 176/11

                                       x = 16

∠R = 5x - 11

   = 5*16 - 11

   = 80 - 11

    = 69

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2 years ago
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Answer:

1

Step-by-step explanation:

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Answer: X= 11

Step-by-step explanation:

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