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N76 [4]
2 years ago
15

What is the slope of the line that passes through the points listed in the table?

Mathematics
1 answer:
Allisa [31]2 years ago
4 0

Answer:

D. -4

Step-by-step explanation:

the slope formula is

m=(y2-y1)/(x2-x1)

(x2,y2) = (4,7)

(x1, y1) = (5,3)

So (7-3)/(4-5) = 4/-1 = -4

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How to find the point slope form with the slope of 3 and the point of -2/6
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\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \:y-6 = 3(x + 2)

____________________________________

\large \tt Solution  \: :

Equation of line in point - slope form :

\qquad \tt \rightarrow \:y-y_1 = m(x - x_1)

  • \tt  \:m = slope=3

  • \tt y_1 = y \:  \: coordinate \:  \: of \:  \: point = 6

  • \tt  \:x_1 = x \:  \: coordinate \:  \: of \:  \: point =  - 2

Here :

\qquad \tt \rightarrow \:y - 6 = 3(x -  ( - 2))

\qquad \tt \rightarrow \:y - 6 = 3(x +  2)

5 0
1 year ago
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Answer:

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when we convert 2x-3y=8 to standard form, we get y= 2/3x-8/3. This means the perpendicular line will have a slope of the negative reciprocal of the original one, so the perpendicular slope is -1.5. When we substitute the points (-2,-4) into the equation y=-1.5x+b, we get a b value of -7. So the perpendicular line equation is y= -1.5x-7. You can't the parallel line equation with the points (-2,-4) as it is part of the line 2x-3y=8.

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Step-by-step explanation:

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