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navik [9.2K]
2 years ago
12

The temperature of a sample of water increases from 20c to 46.6c as it absorbs 5650 Joules of heat. What is the mass of the samp

le
Chemistry
1 answer:
WINSTONCH [101]2 years ago
5 0

Answer: 51 g

Explanation:

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A potassium-40 sample starts with 50 atoms, and 1.25 billion years later, there are 25 atoms. What is the half-life of potassium
guapka [62]
D. 1.25 billion years
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3 years ago
.Florida phosphate accounts for ___ of the world's fertilizer supply?Immersive Reader
Stells [14]

Answer: 25%

Explanation: According to the Florida Industrial and Phosphate Research Institute, Florida’s phosphate mining  accounts for about 75% of the phosphate used in the United States, as well as about 25% phosphate used around the world.  Although first mined in England in 1847, and used as fertilizer, In  1881,  a civilian employee, J Francis Le Baron discovered Phosphate pebbles in peace river, and then, a hard rock phosphate district was discovered in north central Florida after that which began the Phosphate mining industry in Florida. Phosphorus rock  supplies the phosphorus element in the fertilizer mix of nitrogen-phosphorus-potassium that is used as fertilizer to aid in growth of plants.

4 0
3 years ago
Can you help me with this with a solution
LuckyWell [14K]

The complete table is inserted.

A table is given,

Formulas used:

pH=  -log(H⁺)

pOH=  -log(OH⁻)

pH+ pOH=14

Calculations:

For A: (H⁺)=2×10⁻⁸M

Using the pH formula:

pH=  -log(H⁺)=-log(2×10⁻⁸)=7.69

pOH=14 - 7.69=6.3

Calculating OH concentration,

pOH=  -log(OH⁻)

6.3= -log(OH⁻)

(OH⁻)=5.011×10⁻⁷M

Hence, the nature of A is basic.

Similarily,

For B,

(OH⁻)=1×10⁻⁷

Using the pH formula:

pOH=  -log(OH⁻)= -log(1×10⁻⁷)=7

pH=14-7=7

Calculating H concentration,

pH=  -log(H⁺)

7= -log(H⁺)

(H⁺)=1×10⁻⁷M

Hence, the nature of B is neutral.

Similarily,

For C,

pH=12.3

Using the pH formula:

pOH=14-12.3=1.7

Calculating H concentration,

pH=  -log(H⁺)

12.3= -log(H⁺)

(H⁺)=5.011×10⁻¹³M

Calculating OH concentration,

pOH=  -log(OH⁻)

1.7= -log(OH⁻)

(OH⁻)=1.99×10⁻²M

Hence, the nature of C is Basic.

Similarily,

For D,

pOH=6.8

Using the pH formula:

pH=14-6.8=7.2

Calculating H concentration,

pH=  -log(H⁺)

7.2= -log(H⁺)

(H⁺)=6.309×10⁻⁸M

Calculating OH concentration,

pOH=  -log(OH⁻)

6.8= -log(OH⁻)

(OH⁻)=1.58×10⁻⁷M

Hence, the nature of D is basic.

Learn more about the acid and bases here:

brainly.com/question/16189013

#SPJ10

3 0
2 years ago
A 15.75 g piece of iron absorbs 1097 joules of heat energy, and its temperature changes from 25°C to 177°C. Calculate the specif
vekshin1

The answer for the following problem is mentioned below.

Explanation:

Given:

mass of iron (m) = 15.75 grams

heat (q) = 1097 J

initial temperature (t_{1}) = 25°C

final temperature (t_{2}) = 177°C

To find:

specific heat (c)

We know;

 c = q ÷ mΔT

where;

c represents the specific heat

q represents the heat

m represents the mass

t represents the temperature

c = \frac{1097}{15.75 * (177-25)}

c = 0.45 J/kg°C

<u><em>Therefore the specific heat capacity of iron is 0.45 J/kg°C.</em></u>

8 0
4 years ago
Which models of the atom in task 1 are not supported by the results of the hydrogen gas experiment? For each of these models, ex
zysi [14]

Answer: To test the properties of the particles, Thomson placed two oppositely-charged electric plates around the cathode ray. The cathode ray was deflected away from the negatively-charged electric plate and towards the positively-charged plate. This indicated that the cathode ray was composed of negatively-charged particles.

Thomson also placed two magnets on either side of the tube, and observed that this magnetic field also deflected the cathode ray. The results of these experiments helped Thomson determine the mass-to-charge ratio of the cathode ray particles, which led to a fascinating discovery−-−minusthe mass of each particle was much, much smaller than that of any known atom. Thomson repeated his experiments using different metals as electrode materials, and found that the properties of the cathode ray remained constant no matter what cathode material they originated from. From this evidence, Thomson made the following conclusions:

The cathode ray is composed of negatively-charged particles.

The particles must exist as part of the atom, since the mass of each particle is only ~1/2000 the mass of a hydrogen atom.

These subatomic particles can be found within atoms of all elements.

While controversial at first, Thomson's discoveries were gradually accepted by scientists. Eventually, his cathode ray particles were given a more familiar name: electrons. The discovery of the electron disproved the part of Dalton's atomic theory that assumed atoms were indivisible. In order to account for the existence of the electrons, an entirely new atomic model was needed.

8 0
3 years ago
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