Answer:
The mass of ammonia (NH3) that contains hydrogen atoms is g.
Explanation:
As atoms of hydrogen = 1 mole of the hydrogen atom
Therefore, atoms of hydrogen moles of the hydrogen atom.
Now, there are 3 moles of hydrogen atoms in 1 mole of ammonia .
As the mass of 1 mole of ammonia is 17g, so
when there are 3 moles of hydrogen atoms, then the mass of ammonia = 17 g
Therefore, when there are moles of hydrogen atoms, then the mass of ammonia g.
Hence, the mass of ammonia that contains hydrogen atoms is g.
Answer:
Explanation:
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In this case, for this calorimetry problem, since the acetylene is burned into the calorimeter causing a temperature increase, we can infer that the combustion of acetylene releases heat which is absorbed by the calorimeter, therefore, the following equation can be written:
Which can be written in terms of the energy of combustion and moles of the acetylene and the heat capacity and temperature change of the calorimeter:
Thus, since the molar mass of acetylene is 26.04 g/mol, the resulting energy of combustion of the acetylene turns out:
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Answer: M= 128 g/mol (Te is quite close)
Explanation: number of Oxygen moles is n = 8 g / 32 g/mol = 0,25 mol.
Because formula of oxide is MO, thus amount of metal is also 0,25 mol.
Because n = m/M , Molar mass of the metal M = m/n = 32 g /0.25 mol = 128 g/ mol
Answer:
final volume is 60.42 L
Explanation:
given data
initial volume v1 = 58 L
pressure P1 = 1 atm
we take P2 = 40 mbar
solution
we get here final volume
so p2 = 1 - 40 × = 0.96 atm
so
p1 × v1 = p2 × v2 .........1
so put here value
58 × 1 = v2 × 0.96
solve it we get
v2 = 60.42 L