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Aleksandr [31]
3 years ago
9

A 15.75 g piece of iron absorbs 1097 joules of heat energy, and its temperature changes from 25°C to 177°C. Calculate the specif

ic heat capacity of iron
Chemistry
1 answer:
vekshin13 years ago
8 0

The answer for the following problem is mentioned below.

Explanation:

Given:

mass of iron (m) = 15.75 grams

heat (q) = 1097 J

initial temperature (t_{1}) = 25°C

final temperature (t_{2}) = 177°C

To find:

specific heat (c)

We know;

 c = q ÷ mΔT

where;

c represents the specific heat

q represents the heat

m represents the mass

t represents the temperature

c = \frac{1097}{15.75 * (177-25)}

c = 0.45 J/kg°C

<u><em>Therefore the specific heat capacity of iron is 0.45 J/kg°C.</em></u>

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