Question

A 15.75 g piece of iron absorbs 1097 joules of heat energy, and its temperature changes from 25°C to 177°C. Calculate the specific heat capacity of iron

Answer 1

The answer for the following problem is mentioned below.

Explanation:

Given:

mass of iron (m) = 15.75 grams

heat (q) = 1097 J

initial temperature ($t_{1}$) = 25°C

final temperature ($t_{2}$) = 177°C

To find:

specific heat (c)

We know;

 c = q ÷ mΔT

where;

c represents the specific heat

q represents the heat

m represents the mass

t represents the temperature

c = $\frac{1097}{15.75 * (177-25)}$

c = 0.45 J/kg°C

Therefore the specific heat capacity of iron is 0.45 J/kg°C.