Answer:
see below
Step-by-step explanation:
We need to find the diameter of the square
We can find this using the Pythagorean theorem
a^2+b^2 = c^2 where the legs are 7 and 7 and the diameter is c
7^2 +7^2 = c^2
49+49 = c^2
98 = c^2
Taking the square root of each side
sqrt(98) = sqrt(c^2)
9.899494937 = c
Since 9.9 is less than 11 which is the diameter of the circle it will never touch the circle.
Since the longest part of the square is less than the diameter of the circle, the square will fit inside the circle without touching
Solution: Emanuel earns $13 per hour. Also he earns a commission of 5% on all cars he sells.
Number of hours Emanuel worked last month = 40 hours
He sold cars worth $120,000.
Therefore, the total earning of Emanuel is:
Hence, last month Emanuel made $6520, including his hourly pay and commissions.
Answer:
The means is 8.5 The Median is 6
Step-by-step explanation:
1) to find the mean just Simply add all the numbers together and divided by how many numbers that is giving. (Because you are simply finding the average)
9+6+5+3+28+6+4+7=68
68 divided by 8 = 8.5
2) to find the median simply organize the numbers from least to greatest Like this: (3,4,5,6,6,7,9,28) Then keep crossing out from both sides teal you find the middle Number.
If there a odd amount of number the median will be one Number, if even 2 numbers ( if 2 numbers just add them both and divide by 2)
In This Case the Median is 6,6 but Its actually 6 Why (6+6=12) and (12/2=6) so your median is 6.
<em>Hopes This helps!</em>
Answer:
No. Vivian will not make it to her friends house.
Step-by-step explanation:
If Vivian will be riding 15 miles per hour, and she has six hours , then in order to find out the distance, we will have to multiply the rate and the time.
Equation : 15x6 = 90
Using this solution, we can easily find out that 90 is less than 96 as shown.
90<96
In conclusion, no Vivian will not make it to her friends house within the 6 hours she has to get there.
Hope this helps!
I know pi its 3.141595657589793239626448832....
And so on for at least 1000 more numbers
