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2 years ago

Coffee Tea

Mathematics

1 answer:

Lelu [443]2 years ago

3 0

Answer:

A larger percentage of people in New York prefer coffee

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Help!<br>What is the answer to this question?<br><br>

Nadya [2.5K]

Answer:

Step-by-step explanation:

8 0

3 years ago

Laura invests $2500 in one account and $1500 in an account paying 2 % higher interest. At the end of one year she had earned $11

Crank

Answer:

$2500 - 2%

$1500 - 4%

Step-by-step explanation:

Say the interest for the $2500 is x, so the interest for the $1500 is x+0.02.

As an equation, they would look like this:

2500x+1500(x+0.02)=110

Now solve

2500+1500x+30=110

4000x=80

x=0.02

That means the interest for the $2500 is 0.02, or 2%, and the interest for the $1500 is 0.04, or 4%.

6 0

3 years ago

Simplify:<br><img src="https://tex.z-dn.net/?f=2%20%5Cfrac%7B1%7D%7B4%7D%283.5%29%20" id="TexFormula1" title="2 \frac{1}{4}(3.5)

V125BC [204]

9514 1404 393

Answer:

7 7/8

Step-by-step explanation:

There are several ways to get there.

2.25×3.5 = 7.875 = 7 7/8

(2 1/4)(3 1/2) = (9/4)(7/2) = 63/8 = 7 7/8

(2 1/4)(3.5) = 2(3.5) +(1/4)(3.5) = 7 + (2·3.5)/(2·4) = 7 +7/8 = 7 7/8

A typical graphing calculator will let you enter this problem directly, giving you a result either as a decimal, improper fraction, or a mixed number.

4 0

2 years ago

How many pairs of consecutive natural numbers have a product of less than 40000? I am in 5th grade. This is supposed to be easy

Ugo [173]

Answer:

There are 199 pairs of consecutive natural numbers whose product is less than 40000.

Step-by-step explanation:

We notice that such statement can be translated into this inequation:

$n \cdot (n+1) < 40000$

Now we solve this inequation to the highest value of $n$ that satisfy the inequation:

$n^{2}+n < 40000$

$n^{2}+n -40000$

The Quadratic Formula shows that roots are:

$n_{1,2} = \frac{-1\pm\sqrt{1^{2}-4\cdot (1)\cdot (-40000)}}{2\cdot (1)}$

$n_{1,2} = -\frac{1}{2}\pm \frac{1}{2} \cdot \sqrt{160001}$

$n_{1} = -\frac{1}{2}+\frac{1}{2}\cdot \sqrt{160001}$

$n_{1} \approx 199.501$

$n_{2} = -\frac{1}{2}-\frac{1}{2}\cdot \sqrt{160001}$

$n_{2} \approx -200.501$

Only the first root is valid source to determine the highest possible value of $n$ , which is $n_{max} = 199$ . Each natural number represents an element itself and each pair represents an element as a function of the lowest consecutive natural number. Hence, there are 199 pairs of consecutive natural numbers whose product is less than 40000.

6 0

2 years ago

Which of the following is the product of the rational expressions shown here? X/(x+1)*(2/x-1)

Gnom [1K]

Answer:

its B

2×x=2x

(x+1)×(x-1)=x²-x+x-1=x²-1

5 0

2 years ago

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