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3 years ago

Factor sec^2x-secx+tan^2x

Mathematics

1 answer:

marysya [2.9K]3 years ago

6 0

Answer:

sec²(x) - sec(x) + tan²(x) = (sec(x) - 1)(2sec(x) + 1)

Step-by-step explanation:

sec²(x) - sec(x) + tan²(x) =

= sec²(x) - sec(x) + [sec²(x) - 1]

= sec²(x) - sec(x) + [(sec(x) + 1)(sec(x) - 1)]

= sec(x)[sec(x) - 1] + [(sec(x) + 1)(sec(x) - 1)]

= (sec(x) - 1)(sec(x) + sec(x) + 1)

= (sec(x) - 1)(2sec(x) + 1)

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3 years ago

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See below:

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Hello! My name is Galaxy and I will be helping you today, I hope you are having a nice day!

We can solve this in two steps, Comprehension and Solving. I'll go ahead and start with Comprehension.

If you have any questions feel free to ask away!!

Comprehension

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Now that we know what we need to know, we can setup an equation.

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We can do this because first of all, we know that 2x-6 is one of the angles and as per the base angles of an isosceles triangle we know that both base angles are x, therefore we can add 2x to get 180 degrees.

I'll start solving now.

Solving

We can solve this by using the equation we made above and solving it with algebra.

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We know that x is equal to 46.5 degrees. We can check that by inputting it into the equation.

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We've proven that our answer is correct by double checking,

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