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1 year ago

I’m confused on where you got the numbers from. Did you get them from the amount of full squares each shape takes up?

Mathematics

1 answer:

Svetradugi [14.3K]1 year ago

8 0

A square simply means a shape that has four equal sides and four equal angles.

<h3>How to illustrate the square?</h3>

Your information is incomplete. Therefore, an overview of a square will be given.

A square is a quadrilateral. It's also a rectangle that has two equal length adjacent sides. The four angles are equal to 90° each and are congruent to each other.

Learn more about squares on:

brainly.com/question/25092270

#SPJ1

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I need some serious help rn, i got stuck

nordsb [41]

Answer:

I think it is add 11 both sides? If it is wrong i am sooooo sorry

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Find the surface area of the composite figure.

WINSTONCH [101]

Answer:

382 cm²

Step-by-step explanation:

Front face + Back face:

A = 2(a + b)h/2

A = 2(14 cm + 8 cm)(7 cm)/2

A = 154 cm²

Left face:

A = 7 cm × 6 cm = 42 cm²

Right face:

A = 9 cm × 6 cm = 54 cm²

Bottom face:

A = 14 cm × 6 cm = 84 cm²

Top face:

A = 6 cm × 8 cm = 48 cm²

Total surface area =

= (154 + 42 + 54 + 84 + 40) cm²

= 382 cm²

3 0

10 months ago

Let g(x) = 3x + 2. If g(x) = 11, what is x?

astraxan [27]

Answer:

3=x

Step-by-step explanation:

11=3x+2

5 0

2 years ago

Using your knowledge of exponential and logarithmic functions and properties, what is the intensity of a fire alarm that has a s

Ierofanga [76]

Option B:

$I=1.0\times\ 10^{0} \ \text {watts}/ \text m^2}$

Solution:

Given sound level = 120 decibel

To find the intensity of a fire alarm:

$$\beta=10\log\left(\frac{I}{I_0} \right)$

where $I_0=1\times10^{-12}\ \text {watts}/ \text m^2}$

Step 1: First divide the decibel level by 10.

120 ÷ 10 = 12

Step 2: Use that value in the exponent of the ratio with base 10.

$10^{12}$

Step 3: Use that power of twelve to find the intensity in Watts per square meter.

$$10^{12}=\left(\frac{I}{I_0} \right)$

$$10^{12}=\left(\frac{I}{1\times10^{-12}\ \text {watts}/ \text m^2} \right)$

Now, do the cross multiplication,

$I=10^{12}\times1\times\ 10^{-12} \ \text {watts}/ \text m^2}$

$I=1\times\ 10^{12-12} \ \text {watts}/ \text m^2}$

$I=1\times\ 10^{0} \ \text {watts}/ \text m^2}$

$I=1.0\times\ 10^{0} \ \text {watts}/ \text m^2}$

Option B is the correct answer.

Hence $I=1.0\times\ 10^{0} \ \text {watts}/ \text m^2}$ .

5 0

3 years ago

I'm using system of equations and I have to use either substitution or elimination. My two equations are

Svetach [21]

There is no solution. Here is the explanation with both of the methods :)

5 0

2 years ago