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lions [1.4K]
2 years ago
5

Which expression is equal to -4-9?

Mathematics
1 answer:
PtichkaEL [24]2 years ago
4 0

Answer:

-4+(-9)

Step-by-step explanation:

if you have two negatives in an equation next to each other like -4-9 then it is basically adding the two but will just equal a negative sum

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Can <br> a. True <br> b. False results be in a probability distribution
Alexxandr [17]
I think the answers True hope this helps
5 0
4 years ago
How can I solve 900-382?
BlackZzzverrR [31]

   899

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6 0
3 years ago
Kyle asked a random group of students what their favorite sport was. The results are below. Boys Girls Basketball 10 8 Football
Ronch [10]

Answer:

The probability that Kyle will pick a girl who likes football is 12.5%.

Step-by-step explanation:

The data provided is as follows:

                         Boys        Girls       Total

Basketball          10             8             18

 Football           25             7             32

  Soccer             9             19             28

 Baseball           18            22            40

   Total               62           56            118

Compute the probability that Kyle will pick a girl who likes football as follows:

P(F|G)=\frac{n(G\cap F)}{n(G)}

            =\frac{7}{56}\\\\=0.125\\\\=12.5\%

Thus, the probability that Kyle will pick a girl who likes football is 12.5%.

6 0
3 years ago
A tree is 6 feet tall now. It is expected to grow 3 feet per year. In how many years is the tree expected to be 75 feet tall
Alik [6]
I dont know its right but i did 
6+3*23=75

8 0
3 years ago
Write as a product: 25a2−0.01b10
Yakvenalex [24]

Answer:

We conclude that:

25a^2-0.01b^{10}=\left(5a+0.1b^5\right)\left(5a-0.1b^5\right)

Step-by-step explanation:

Given the expression

25a^2-0.01b^{10}

Rewrite 25a^2-0.01b^{10} as \left(5a\right)^2-\left(\sqrt{0.01}b^5\right)^2

so

25a^2-0.01b^{10}=\left(5a\right)^2-\left(\sqrt{0.01}b^5\right)^2

Apply difference of two squares formulas:

x^2-y^2=\left(x+y\right)\left(x-y\right)

so

\left(5a\right)^2-\left(\sqrt{0.01}b^5\right)^2=\left(5a+\sqrt{0.01}b^5\right)\left(5a-\sqrt{0.01}b^5\right)

                               =\left(5a+0.1b^5\right)\left(5a-0.1b^5\right)    ∵ \sqrt{0.01}=0.1,

Therefore, we conclude that:

25a^2-0.01b^{10}=\left(5a+0.1b^5\right)\left(5a-0.1b^5\right)

7 0
3 years ago
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