Question

There were 480 people at play. The admission price was $2 for adults and $1 for children. The admission receipts were $770. How many adults and how many children attended?

Answer 1

Answer:

290 adults and 190 children attended the Play.

Step-by-step explanation:

Given:

Total number of people in play = 480

Let the number of adults be x

and Number of children be y

Hence we can write the equation as;

$x+y=480 \ \ \ \ equation \ 1$

Also Given:

Price for 1 adult = $2

Price for 1 children = $1

Total admission receipts = $770

Hence we can write the equation as;

$2x+y =770 \ \ \ \ equation \ 2$

Now We will subtract equation 1 from equation 2 we get;

$(2x+y)- (x+y) =770-480\\2x+y-x-y= 290\\x= 290$

Now substituting the value of x in equation 1 we get;

$290+y =480\\y =480 -290\\y= 190$

Hence 290 adults and 190 children attended the Play.