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Stells [14]
4 years ago
5

Find the hcf of 15a²b² and -24ab | plzzz solve

Mathematics
1 answer:
tino4ka555 [31]4 years ago
5 0

Answer:

\large \boxed{\sf \ \ \ 3\cdot a \cdot b \ \ \ }

Step-by-step explanation:

Hello,

First of all, let's find the factors of these two numbers and I will put <u>in boxes the common factors.</u>

15a^2b^2=\boxed{3}\cdot 5\cdot \boxed{a} \cdot a \cdot \boxed{b} \cdot b \\ \\ \\-24ab=(-1)\cdot 2 \cdot \boxed{3} \cdot 4 \cdot \boxed{a} \cdot \boxed{b}

The Highest Common Factor (HCF) is found by finding all common factors and selecting the largest one. So, in this case, it gives

\large \boxed{\sf \ \ \ 3\cdot a \cdot b \ \ \ }

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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C. For every 2 red candies in a bag, there are 3 green candies.

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A ratio always contains 2 figures.

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A number divided by 14
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x÷14

Step-by-step explanation:

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<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B9x%2B20%3D0" id="TexFormula1" title="x^{2} +9x+20=0" alt="x^{2} +9x+20=0" ali
Hoochie [10]

Answer:

We have been given an equation x^2+9x+20=0

We will factorize it by  middle term splitting.

Step 1: x^2+5x+4x+20=0

Taking common factors out by clubing first two terms ad last two terms

Step 2: x(x+5)+4(x+5)=0

Step 3: (x+4)(x+5)=0

Equating both above factors to zero as:

Step 4: (x+4)=0\Rightarrow x=-4

   And (x+5)=0\Rightarrow x=-5.

3 0
3 years ago
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Você é um comandante de uma espaçonave. Sua missão é chegar até Alfa Centauro em cinco anos. A distância do Sol até Alfa Centaur
Deffense [45]

Answer:

The spaceship will get to Alpha Centaur in time

Step-by-step explanation:

<u><em>The complete question in English is</em></u>

You're the commander of a spaceship. Your mission is to reach Alpha Centaur  in five years. The distance from the sun to Alpha Centaur is 2.5 x 10^13 miles. The distance  from Earth to Sun is approximately 9.3 x 10^7

miles. Your spaceship can travel  at the speed of light. You know that light can travel a distance of 5.88 x 10^12  miles in a year. Can you get to Alpha Centaur in time?

step 1

Find the time it takes for the spaceship to travel from Earth to the Sun

The distance from the Earth to Sun is equal to

9.3*10^7\ miles

The spaceship can travel  at the speed of light

The light can travel a distance of 5.88*10^{12}\ miles in a year

so

using a proportion

\frac{5.88*10^{12}\ miles}{1\ year}=\frac{9.3*10^7\ miles}{x}\\\\x=(9.3*10^7)/5.88*10^{12}\\\\x=1.58*10^{-5} \ years

This time is very small in years

Convert to minutes

1.58*10^{-5} \ years=1.58*10^{-5} (365)(24)(60)=8.3\ min

step 2

Find the time it takes for the spaceship to travel from the Sun to Alpha Centaur

The distance from the the Sun to Alpha Centaur is equal to

2.5*10^{13}\ miles

The spaceship can travel  at the speed of light

The light can travel a distance of 5.88*10^{12}\ miles in a year

so

using a proportion

\frac{5.88*10^{12}\ miles}{1\ year}=\frac{2.5*10^{13}\ miles}{x}\\\\x=(2.5*10^{13})/5.88*10^{12}\\\\x=4.25\ years

4.25\ years< 5\ years

therefore

The spaceship will get to Alpha Centaur in time

3 0
3 years ago
For questions 3 – 5, an airplane is heading south at an airspeed of 540 km/hr, but there is a wind blowing from the northeast at
GuDViN [60]

First, let's calculate the horizontal and vertical components of the wind speed (W) and the airplane speed (A), knowing that south is a bearing of 270° and northeast is a bearing of 45°:

\begin{gathered} W_x=W\cos45°\\ \\ W_x=50\cdot0.707\\ \\ W_x=35.35\\ \\ \\ \\ W_y=W\sin45°\\ \\ W_y=50\cdot0.707\\ \\ W_y=35.35 \end{gathered}\begin{gathered} A_x=A\cos270°\\ \\ A_x=540\cdot0\\ \\ A_x=0\\ \\ \\ \\ A_y=A\sin270°\\ \\ A_y=540\cdot(-1)\\ \\ A_y=-540 \end{gathered}

Now, let's add the components of the same direction:

\begin{gathered} V_x=W_x+A_x=35.35+0=35.35\\ \\ V_y=W_y+A_y=35.35-540=-504.65 \end{gathered}

To find the resultant bearing (theta), we can use the formula below:

\begin{gathered} \theta=\tan^{-1}(\frac{V_y}{V_x})\\ \\ \theta=\tan^{-1}(\frac{-504.65}{35.35})\\ \\ \theta=-86° \end{gathered}

The angle -86° is equivalent to -86 + 360 = 274°.

Therefore the correct option is b.

8 0
1 year ago
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