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Stells [14]
3 years ago
5

Find the hcf of 15a²b² and -24ab | plzzz solve

Mathematics
1 answer:
tino4ka555 [31]3 years ago
5 0

Answer:

\large \boxed{\sf \ \ \ 3\cdot a \cdot b \ \ \ }

Step-by-step explanation:

Hello,

First of all, let's find the factors of these two numbers and I will put <u>in boxes the common factors.</u>

15a^2b^2=\boxed{3}\cdot 5\cdot \boxed{a} \cdot a \cdot \boxed{b} \cdot b \\ \\ \\-24ab=(-1)\cdot 2 \cdot \boxed{3} \cdot 4 \cdot \boxed{a} \cdot \boxed{b}

The Highest Common Factor (HCF) is found by finding all common factors and selecting the largest one. So, in this case, it gives

\large \boxed{\sf \ \ \ 3\cdot a \cdot b \ \ \ }

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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hram777 [196]

Answer:

0.58 is larger

Step-by-step explanation:

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3 years ago
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Richard spends a total of $105.93 for 3 video games and 2 DVDs. The video games are each the same price, and he pays $12.75 for
-Dominant- [34]
32.43 is dvd plus tax subtract from 105.93 is 73.50 divided by 3 video games is $24.50 for a video game
5 0
3 years ago
The sum of two terms of gp is 6 and that of first four terms is 15/2.Find the sum of first six terms.​
Gnoma [55]

Given:

The sum of two terms of GP is 6 and that of first four terms is \dfrac{15}{2}.

To find:

The sum of first six terms.​

Solution:

We have,

S_2=6

S_4=\dfrac{15}{2}

Sum of first n terms of a GP is

S_n=\dfrac{a(1-r^n)}{1-r}              ...(i)

Putting n=2, we get

S_2=\dfrac{a(1-r^2)}{1-r}

6=\dfrac{a(1-r)(1+r)}{1-r}

6=a(1+r)                    ...(ii)

Putting n=4, we get

S_4=\dfrac{a(1-r^4)}{1-r}

\dfrac{15}{2}=\dfrac{a(1-r^2)(1+r^2)}{1-r}

\dfrac{15}{2}=\dfrac{a(1+r)(1-r)(1+r^2)}{1-r}

\dfrac{15}{2}=6(1+r^2)            (Using (ii))

Divide both sides by 6.

\dfrac{15}{12}=(1+r^2)

\dfrac{5}{4}-1=r^2

\dfrac{5-4}{4}=r^2

\dfrac{1}{4}=r^2

Taking square root on both sides, we get

\pm \sqrt{\dfrac{1}{4}}=r

\pm \dfrac{1}{2}=r

\pm 0.5=r

Case 1: If r is positive, then using (ii) we get

6=a(1+0.5)  

6=a(1.5)  

\dfrac{6}{1.5}=a  

4=a

The sum of first 6 terms is

S_6=\dfrac{4(1-(0.5)^6)}{(1-0.5)}

S_6=\dfrac{4(1-0.015625)}{0.5}

S_6=8(0.984375)

S_6=7.875

Case 2: If r is negative, then using (ii) we get

6=a(1-0.5)  

6=a(0.5)  

\dfrac{6}{0.5}=a  

12=a  

The sum of first 6 terms is

S_6=\dfrac{12(1-(-0.5)^6)}{(1+0.5)}

S_6=\dfrac{12(1-0.015625)}{1.5}

S_6=8(0.984375)

S_6=7.875

Therefore, the sum of the first six terms is 7.875.

5 0
3 years ago
1.2.6 1-118 Find each sum.<br><br> A. 3/5 + 1/3<br><br> B. 5/7 + 1/2<br><br> C. 1/6 + 2/8
Blababa [14]
A.) 14/15 B.) 17/14 C.) 5/12
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3 years ago
Find the area. Around your answer to decimal places​
alexgriva [62]
  • Answer:

<em>86.20 ft²</em>

  • Step-by-step explanation:

<em>Hi there !</em>

<em>A = A₁ + A₂</em>

<em>A₁ =semicircle</em>

<em>A₁ = πr²/2</em>

<em>r = d/2 = 6.4ft/2 = 3.2 ft</em>

<em>A₁ = 3.14×(3.2ft)²/2 ≈ 32.15 ft²</em>

<em />

<em>A₂ =  trapezium</em>

<em>A₂ = (b + B)×h/2</em>

<em>A₂ = (5.1ft + 6.4ft)×9.4ft/2 = 54.05 ft²</em>

<em />

<em>A = 32.15 ft² + 54.05 ft² = 86.20 ft²</em>

<em>Good luck !</em>

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