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2 years ago

Answer fast pls .....

Mathematics

1 answer:

Fudgin [204]2 years ago

3 0

1. the perimeter of a square is always 4 * side, so = 4*31/8 = 31/2 or 15 and 1/2
2. area of a square is always the side multiplied by each other, so: 9/2 * 9/2 = 81/4 or 20 and 1/4

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how many outcomes are possible if you choose one of each kind of stuffed animal from 4 bunnies, 3 monkeys, and 3 racoons?

Ilya [14]

10 Bc if u add them all up it equals that

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3 years ago

Use the numbers 5,6, and 7 and the operations of addition,subtraction, multiplication, and/or division to create three different

mars1129 [50]

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2. 6x7+5

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5 0

3 years ago

Read 2 more answers

An angle measure of 55.45 is converted to DMS notation as

jek_recluse [69]

Converting angle measure of 55.45 to DMS notation we get 55 degrees 27 minutes 0 seconds

Step-by-step explanation:

We need to convert angle measure of 55.45 to DMS notation

DMS notation is Degree Minute and seconds

Solving:

We have 55.45, the value before decimal is considered as degrees and values after decimal can be minutes and seconds.

We can write it as 55 and 0.45

So, we have 55 degrees

To find minutes we will multiply 0.45 by 60

0.45*60 = 27 minutes

Since we have no decimal value in minutes so seconds will be 0

So, DMS will be 55 degrees 27 minutes 0 seconds

Hence converting angle measure of 55.45 to DMS notation we get 55 degrees 27 minutes 0 seconds

5 0

3 years ago

Please help me to prove this! I need is no.(c). So, please help me do it.

zloy xaker [14]

Answer: see proof below

Step-by-step explanation:

Given: A + B + C = 90° → A + B = 90° - C

→ C = 90° - (A + B)

Use the Double Angle Identity: cos 2A = 1 - 2 sin² A

→ sin² A = (1 - cos 2A)/2

Use Sum to Product Identity: cos A + cos B = 2 cos [(A + B)/2] · cos [(A - B)/2]

Use the Product to Sum Identity: cos (A - B) - cos (A + B) = 2 sin A · sin B

Use the Cofunction Identities: cos (90° - A) = sin A

sin (90° - A) = cos A

Proof LHS → RHS:

LHS: sin² A + sin² B + sin² C

$\text{Double Angle:}\qquad \dfrac{1-\cos 2A}{2}+\dfrac{1-\cos 2B}{2}+\sin^2 C\\\\\\.\qquad \qquad \qquad =\dfrac{1}{2}\bigg(2-\cos 2A-\cos 2B\bigg)+\sin^2 C\\\\\\.\qquad \qquad \qquad =1-\dfrac{1}{2}\bigg(\cos 2A+\cos 2B\bigg)+\sin^2 C$

$\text{Sum to Product:}\quad 1-\dfrac{1}{2}\bigg[2\cos \bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A-2B}{2}\bigg)\bigg]+\sin^2 C\\\\\\.\qquad \qquad \qquad =1-\cos (A+B)\cdot \cos (A-B)+\sin^2 C$

Given: 1 - cos (90° - C) · cos (A - B) + sin² C

Cofunction: 1 - sin C · cos (A - B) + sin² C

Factor: 1 - sin C [cos (A - B) + sin C]

Given: 1 - sin C[cos (A - B) - sin (90° - (A + B))]

Cofunction: 1 - sin C[cos (A - B) - cos (A + B)]

Sum to Product: 1 - sin C [2 sin A · sin B]

= 1 - 2 sin A · sin B · sin C

LHS = RHS: 1 - 2 sin A · sin B · sin C = 1 - 2 sin A · sin B · sin C $\checkmark$

6 0

3 years ago

I need help with this my brain cant comprehend

Rom4ik [11]

The function is symmetric in the line that goes trough the top. The top is on t=2.5 seconds. If you want to know on which time the height is equal to 15 feet, you draw a line on that height in the graph and see where it crosses. That is at t=1.25 and t=3.75

8 0

2 years ago