To solve this, we are going to use the surface are of a sphere formula:
where
is the surface area of the sphere
is the radius of the sphere
We know for our problem that
and
, so lets replace those vales in our formula:
Now, we just need to solve our equation for
:
or
Since the radius of a sphere cannot be a negative number,
.
We can conclude that the radius of a sphere with surface area <span>2,122.64 </span>
is
13 in.
We have three numbers to arrange so that 6 is 1/10 of the value of the other six.
Since position tells us whether we're talking about single, tens, hundreds, thousands (e.g. 25 is two times 10 plus five times 1) we know that the two sixes must be next to each other.
This leaves us with two options.
663 or 366.
In each of these cases the second 6 in the number is one tenth of the first 6.
If we look at the only other option: 636 we see that the second 6 is one hundredth of the value of the first 6.
Answer:
C
Explanation:
B=Base Area
In a cylinder, the base area is a circle.
Area Circle=pi r^2
Replace base area with area of circle:
V=pi r^2 H
<span>The method of solving "by substitution" works by solving one of the equations (you choose which one) for one of the variables (you choose which one), and then plugging this back into the other equation, "substituting" for the chosen variable and solving for the other. Then you back-solve for the first variable.</span>
Answer:
x = 13°
Step-by-step explanation:
m<EGF + m< FGH = m<EGH
or, 3x+6+5x-7 = 103°
or, 8x-1 = 103°
or, 8x = 103°+1°
or, x = 104°/8
or, x = 13°
Now,
m<EGF = 3x+6
= 3×13+6
= 39+6
= 45
m<FGH = 5x-7
= 5×13-7
= 65-7
= 58
