Solve: 2a + 6 = 12 a =
1 answer:
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ANSWER
Find out the how many pounds of nickel have to be used to create alloy that contains 4.9 lb of zinc.
To proof
As given
An alloy consists of nickel, zinc, and copper in the ratio 2:7:9.
the total part of the alloy are 18.
assuming one part be x.
thus
nickel part = 2x
zinc part = 7x
copper part = 9x
alloy that contains 4.9 lb of zinc.
than the equation becomes
7x = 4.9
x = 0.7
Therefore
nickel part = 2x
= 2× 0.7
= 1.4 lb
1.4 lb of nickel have to be used to create alloy that contains 4.9 lb of zinc.
Hence proved
The cylinder is symmetric across the plane 
, so we need only consider half of the cut-out region.
This region can be parameterized by
with
and 
. Then the area of this half is given by the surface integral
Doubling this gives a total area of 72.
This region can be parameterized by
with
Doubling this gives a total area of 72.
Answer:
Step-by-step explanation:
Let's start with the simple ones:
a = amplitude = (highest - lowest) divided by 2 = (11-1)/2 = 5
d = offset = (highest + lowest) divided by 2 = (11+1)/2 = 6
Now, if x goes 'untreated', the cos would make a full swing after 2pi.
Here, it repeats after 3. To achieve that, we divide by 3 and multiply by 2pi.
b = 2pi/3
You can try it out (assuming c=0 for a minute): x=3 puts bx at 2pi.
Now for the final one, the shift left by one. We cannot say c=1 because that would be a 1 on the 2pi scale.
Rather, the shift would be c'=1 if the formula were acos(b(x+c')).
If we work out the parenthesis with c'=1, we get bx + b, so the actual c is 2pi/3