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vodomira [7]
4 years ago
7

What is the lcm of 6and 15

Mathematics
2 answers:
Maurinko [17]4 years ago
5 0
LCM stands for least common multiple. We are being asked to find the lowest multiple that 6 and 15 have in common.

Multiples of a number (n) are integers that are the product of n and another number. Let's list the multiples of both 6 and 15:

6: 6, 12, 18, 24, 30, 36

15: 15, 30, 45, 60, 75, 90

The LCM of 6 and 15 is 30.
tatiyna4 years ago
4 0
It should be 30 if im not wrong.
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A is one of the true statements because 25 is the largest number that 50 and 75 can both divide evenly into.

D is the other true statement because 45 is the lowest number that 5 and 9 can both multiply into.

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What is -3 (4n+2)=3<br>N=
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jamie is making chocolate cupcakes. the recipe calls for 2/3 cup of cocoa. she wants to make 1/2 of the recipe. how much cocoa w
Masja [62]

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I think its 1/3

Step-by-step explanation:

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3 years ago
over three successive Collins build 1/3, 1/5 and 1/4 of the brickwork of his new garage. What fraction must he complete on the f
garri49 [273]

Answer:

1 - 1/3 - 1/4 - 1/5

Step-by-step explanation:

Let's take it one step at a time.

Day 1 he completes 1/3 of the garage, so you subtract 1/3 from 1 which means he left 2/3

Day 2 he completed 1/4 more, so you again subtract, this time though 2/3 - 1/4, or in other words 1 - 1/3 - 1/4

So you do this one more time.  1 - 1/3 - 1/4 - 1/5

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5 0
3 years ago
Suppose that prices of a certain model of a new home are normally distributed with a mean of $150,000. Use the 68-95-99.7 rule t
levacccp [35]

Answer:

68% of buyers paid between $147,700 and $152,300.

Step-by-step explanation:

We are given that prices of a certain model of a new home are normally distributed with a mean of $150,000.

Use the 68-95-99.7 rule to find the percentage of buyers who paid between $147,700 and $152,300 if the standard deviation is $2300.

<u><em>Let X = prices of a certain model of a new home</em></u>

SO, X ~ Normal(\mu=150,000 ,\sigma=2,300)

The z score probability distribution for normal distribution is given by;

                             Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean price = $150,000

            \sigma = standard deviation = $2,300

<u>Now, according to 68-95-99.7 rule;</u>

Around 68% of the values in a normal distribution lies between \mu-\sigma and \mu-\sigma.

Around 95% of the values occur between \mu-2\sigma and \mu+2\sigma .

Around 99.7% of the values occur between \mu-3\sigma and \mu+3\sigma.

So, firstly we will find the z scores for both the values given;

         Z  =  \frac{X-\mu}{\sigma}  =  \frac{147,700-150,000}{2,300}  = -1

         Z  =  \frac{X-\mu}{\sigma}  =  \frac{152,300-150,000}{2,300}  = 1

This indicates that we are in the category of between \mu-\sigma and \mu-\sigma.

SO, this represents that percentage of buyers who paid between $147,700 and $152,300 is 68%.

7 0
4 years ago
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