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2 years ago

Help me and there will be an apple at your doorstep. (There might be some shipping issues)

Mathematics

2 answers:

Rashid [163]2 years ago

8 0

Answer:

9.30

Step-by-step explanation:

Alexeev081 [22]2 years ago

3 0

Answer:

9.30 maybe

Step-by-step explanation:

I just did mathz

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Write the formula to find the length of the rectangle and then solve.

Galina-37 [17]

Answer:

Formula-W=A/L

Legnth-17

Step-by-step explanation:

Using the formula to find width of a rectangle, (width= area divided by legnth), you get 17. You can check by multiplying 26 by 17 to get 442. Hope this helps (ﾉ◕ヮ◕)ﾉ*:･ﾟ✧

8 0

3 years ago

Read 2 more answers

The function h (d) = 2d + 4.3 relates the height (h) of the water in a fountain in feet to the diameter (d) of the pipe carrying

mezya [45]

Answer:

h(1.5) = 7.3 ft

h(10.3) = 24.9 ft

Step-by-step explanation:

Given the function h(d) = 2d + 4.3,

where:

h = height of the water in a fountain (in feet)

d = diameter of the pipe carrying the water (in inches)

Substitute the input value of d = 1.5, into the function:

h(1.5) = 2(1.5) + 4.3

h(1.5) = 3 + 4.3

h(1.5) = 7 feet

The height of the water in a fountain is 7 feet when the diameter of the pipe is 1.5 inches.

Substitute the input value of d = 10.3, into the function:

h(10.3) = 2(10.3) + 4.3

h(10.3) = 20.6 + 4.3

h(10.3) = 24.9 feet

The height of the water in a fountain is 24.9 feet when the diameter of the pipe is 10.3 inches.

<h3>Context of the solutions to h(1.5) and h(10.3):</h3>

The solutions to both functions show the relationship between the diameter of the pipe to the height of the water in a fountain. The height of the water in fountain increases relative to the diameter of the pipe. In other words, as the diameter or the size of the pipe increases or widens, the height of the water in a fountain also increases.

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2 years ago

The annual rainfall in a certain region is approximately normally distributed with mean 41.8 inches and standard deviation 5.8 i

kicyunya [14]

I believe the answer would be B

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2 years ago

What is the slip of the line 4x-2y=5

Eddi Din [679]

If you mean slope.. the equation to set up is y=mx+b. Using this, and finding out the answer m=2.

Hope this helped!

4 0

3 years ago

Find the mass and center of mass of the lamina that occupies the region D and has the given density function rho. D is the trian

Alla [95]

Answer: mass (m) = 4 kg

center of mass coordinate: (15.75,4.5)

Step-by-step explanation: As a surface, a lamina has 2 dimensions (x,y) and a density function.

The region D is shown in the attachment.

From the image of the triangle, lamina is limited at x-axis: 0≤x≤2

At y-axis, it is limited by the lines formed between (0,0) and (2,1) and (2,1) and (0.3):

<u>Points (0,0) and (2,1):</u>

y = $\frac{1-0}{2-0}(x-0)$

y = $\frac{x}{2}$

<u>Points (2,1) and (0,3):</u>

y = $\frac{3-1}{0-2}(x-0) + 3$

y = -x + 3

Now, find total mass, which is given by the formula:

$m = \int\limits^a_b {\int\limits^a_b {\rho(x,y)} \, dA }$

Calculating for the limits above:

$m = \int\limits^2_0 {\int\limits^a_\frac{x}{2} {2(x+y)} \, dy \, dx }$

where a = -x+3

$m = 2.\int\limits^2_0 {\int\limits^a_\frac{x}{2} {(xy+\frac{y^{2}}{2} )} \, dx }$

$m = 2.\int\limits^2_0 {(-x^{2}-\frac{x^{2}}{2}+3x )} \, dx }$

$m = 2.\int\limits^2_0 {(\frac{-3x^{2}}{2}+3x)} \, dx }$

$m = 2.(\frac{-3.2^{2}}{2}+3.2-0)$

m = 2(-4+6)

m = 4

<u>Mass of the lamina that occupies region D is 4.</u>

<u />

Center of mass is the point of gravity of an object if it is in an uniform gravitational field. For the lamina, or any other 2 dimensional object, center of mass is calculated by:

$M_{x} = \int\limits^a_b {\int\limits^a_b {y.\rho(x,y)} \, dA }$