2 years ago

HELP ASAP!! PLEASE SHOW STEPS!!!

1 answer:

6 0

I assume you just have to simplify the expression.

$\dfrac{(4\times 10^{-5}) + (2 \times 10^{-5})}{3\times10^7} = \dfrac{6\times10^{-5}}{3\times10^7} = \boxed{2\times 10^2}$

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The product of (1/2+3/4)(1/2-3/4)(i) and divided by (2-3i) is (multiplying complex numbers)

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b. Demonstrate that the two expressions are equivalent by substituting a with the value of 4, and then complete the sentence bel

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Write (1/3i)-(-6+2/3i) as a complex number in standard form

Eddi Din [679]

Answer:

$6+\frac{i}{3}$

Step-by-step explanation:

$\frac{1}{3\imath}-(-6+\frac{2}{3\imath})$

$\frac{1}{3\imath}+6-\frac{2}{3\imath}$

taking like terms together

$\frac{1}{3\imath}-\frac{2}{3\imath}+6$

taking LCM

$\frac{1-2}{3\imath}+6$

$\frac{-1}{3\imath}+6$

taking LCM

$\frac{-1+18\imath}{3\imath}$

splitting the term

$\frac{-1+18\imath}{3\imath}$

splitting the term

$-\frac{1}{3\imath}+\frac{18\imath}{3\imath}$

$-\frac{1\times3\imath}{3\imath \times \imath}+6$

$-\frac{i}{3\imath^2}+6$

we know that

$\imath^2=-1$

putting this value in above equation

$\frac{\imath}{3}+6$

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3 years ago