. Consider the circle with equation (x – 12)2+(y – 12)2=100. a) What is the center of this circle?

1 answer:

6 0

The equation of a circle is (x - h)² + (y - k)² = r²
(h, k) is the center of the circle
SO since h is 12 and k is 12, the center of the circle must be (12, 12)
For extra info, the radius is √100 so r = 10

You might be interested in

1. If a quadratic expression has x-intercepts of

vlada-n [284]

B. Standard form

Hope this helps

6 0

3 years ago

What are the excluded values of x for x+4/-3x^2+12x+36

LekaFEV [45]

I will assume that you meant:

(x+4)/(-3x^2+12x+36) factor the denominator...

(x+4)/(-3(x^2-4x-12))

To factor a quadratic of the form ax^2+bx+c you need to find two values, j and k, which satisfy two conditions...

jk=ac=-12 and j+k=b=-4 so j and k must be 2 and -6 and the factors are then:

(x+2)(x-6) so we are now left with:

(x+4)/(-3(x+2)(x-6))

The only restriction on this function is that division by zero is undefined, so x cannot equal -2 or 6

3 0

4 years ago

Read 2 more answers

THE RIGHT ANSWER WILL RECEIVE A BRAIN-LEST, THANX AND VOTES AND POINTS!!!!!!

sladkih [1.3K]

the 1st on is 16. the 2nd is 15. She went to the 1st doctor more times

8 0

3 years ago

The solution for the following system of equations is shown on the graph. What is the solution?

Bingel [31]

The solution is (3 , 4) ⇒ 2nd answer

Step-by-step explanation: