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Over [174]
2 years ago
9

Based on the work provided, write the dividend as a product of two factors

Mathematics
1 answer:
GenaCL600 [577]2 years ago
4 0

Answer:

x4+2x3+x2+5x+b=x-2x3+x+3

Step-by-step explanation:

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Find the area of the figure. Round it to the nearest hundredth
aliya0001 [1]

Answer:

Please add the figure by clicking on the link button when posting something

Step-by-step explanation:

4 0
3 years ago
Find the x- and y-intercept of the line.<br><br> -4x +2y = 24
Daniel [21]
When y = 0,  x will equal the x-intercept. So, plug in 0 for the y-value to find the x-intercept.

  -4x + 2y = 24   Plug in 0 for y
-4x +2(0) = 24   Multiply
          -4x = 24   Divide both sides by -4
             x = -6

The x-intercept is (-6, 0).

When x = 0, y will be the y-intercept. So, plug in 0 for x and solve for y.

   -4x + 2y = 24   Plug in 0 for x
-4(0) + 2y = 24   Multiply
           2y = 24   Divide both sides by 2
             y = 12

The y-intercept is (0, 12).
4 0
3 years ago
<img src="https://tex.z-dn.net/?f=Find%20%7D%20%5Csum%20r%5E%7B2%7D%20%5Ccdot%7B%20%7D%5E%7B20%7D%20C_%7Br%7D%5Cend%7Bequation%7
Serggg [28]

I bet the sum you're referring to is supposed to be

\displaystyle \sum_{r=0}^{20} r^2 \times {}^{20}C_r

or equivalently,

\displaystyle \sum_{r=0}^{20} r^2 \binom{20}r

where \binom nk = \frac{n!}{k!(n-k)!} is the binomial coefficient.

Recall the binomial series,

(1+x)^\alpha = \displaystyle \sum_{r=0}^\infty \binom\alpha r x^r

which is valid for |x| < 1. (Note that if r > α, the binomial coefficient is defined to be zero, so there really are only α many terms when α is a whole number.)

Differentiating both sides with respect to x gives

\alpha (1+x)^{\alpha-1} = \displaystyle \sum_{r=0}^\infty r \binom\alpha r x^{r-1}

Multiply both sides by some arbitrary x in |x| < 1 :

\alpha x (1+x)^{\alpha-1} = \displaystyle \sum_{r=0}^\infty r \binom\alpha r x^r

Repeat:

\alpha (1+x)^{\alpha-1} + \alpha(\alpha-1) x(1+x)^{\alpha-2} = \displaystyle \sum_{r=0}^\infty r^2 \binom\alpha r x^{r-1}

\alpha x (1+x)^{\alpha-1} + \alpha(\alpha-1) x^2 (1+x)^{\alpha-2} = \displaystyle \sum_{r=0}^\infty r^2 \binom\alpha r x^r

Let α = 20, and let x approach 1 from below. The right side converges to the sum we want, while the left side converges to

20 \times 2^{19} + 20\times19\times 2^{18} = (20 + 10\times19)\times2^{19} = \boxed{210\times2^{19}}

5 0
2 years ago
Is x=-7 an equation that describes a function
san4es73 [151]
Xy + 7<span> = </span>x<span> + y is not a linear </span>equation<span> because the term xy has degree 2. </span>x<span> + 3y</span>2<span> = 6 is not a linear</span>equation<span> because the term 3y</span>2<span> has degree 2. ... </span>x<span> = (constant). is a linear </span>equation<span> but does not</span><span>describe a function</span>
5 0
3 years ago
Read 2 more answers
Which table of ordered pairs, when plotted, will form a straight line. Select all that apply
Elina [12.6K]

Answer:

Rrrororırırıtrfofofıgıtıg

4 0
3 years ago
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