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3 years ago

I really need someone to do this I can’t figure it out

Mathematics

1 answer:

faust18 [17]3 years ago

6 0

Area of two traingles

2(1/2BH)
BH
6(5)
30cm²

Area of Two rectangles

2LB

2(8)(5)
80cm²

LSA

80+30
110cm²

TSA

2(LB+BH+LH)
2(5×3+3×6+6×5)
2(15+18+30)
2(63)
126cm²

r=8.4/2=4.2cm

h=10.9cm

LSA

2πrh
2π(4.2)(10.9)
287.5cm²

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Select the correct answer.

Taya2010 [7]

The answer for this is c

8 0

3 years ago

HELP I NEED HELP ASAP

Natalija [7]

Answer:

A) (2,5)

Step-by-step explanation:

longest side is between points (1,4) and (3,6)

so midpoint is ((1+3)/2), ((4+6)/2), which equals (2, 5)

8 0

3 years ago

96 16 81 = x 11 15 18 = y what is the value of y-2x?

qwelly [4]

Hey, im not really sure but i think it is that 1. x=96 y=11 2. x=16 y=15 3.x=81 y=18
Then you just substitute the numbers into the letters. For example,

11-96(2)= -181

15-16(2)= -17

18-81(2)= -144

3 0

3 years ago

If the parent function f(x) = x^2 is fatter translated 11 units to the left, then translated 5 units down, write the resulting f

nikklg [1K]

The quadratic function given by:

$f(x)=a(x-h)^2+k, \ \ \ a\neq 0$

is in vertex form. The graph of $f$ is a parabola whose axis is the vertical line $x=h$ and whose vertex is the point $(h, k)$ . So:

To translate the graph of a function to the right, left, upward or downward we have:

$For \ a \ positive \ real \ number \ c. \ \mathbf{Vertical \ and \ horizontal \ shifts} \\ in \ the \ graph \ of \ y=f(x) \ are \ represented \ as \ follows:\\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{upward}: \\ g(x)=f(x)+c \\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{downward}: \\ g(x)=f(x)-c \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{right}: \\ g(x)=f(x-c) \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{left}: \\ g(x)=f(x+c)$

By knowing this things, we can solve our problem as follows:

FIRST.

Translating 11 units to the left:

$g(x)=f(x+11) \\ \\ \therefore g(x)=(x+11)^2$

Then translating 5 units down:

$g(x)=f(x)-c \\ \\ \therefore g(x)=(x+11)^2-5$

Since the new function is fatter, the factor we need to multiply the term $(x+11)^2$ must be less than 1, to make the graph fatter. So, according to our options, there are two factors 1/2 and 2.