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nasty-shy [4]
2 years ago
9

How does cool roofs help the co2?

Physics
1 answer:
Hoochie [10]2 years ago
7 0

Answer:

These cool down not only the house but even helps with the potential of canceling the heating effect of up to two years of worldwide carbon dioxide emissions. Which would over help the co2 rates.

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Consider the circuit below, which is powered by a 6-v battery. switch s is opened at t = 0 after having been closed for a long t
Semmy [17]
The answer should be B 
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3 years ago
Researchers want to see if college students are more committed to their fraternity after going through a hazardous hazing ritual
Mila [183]

Answer:

College student's commitment

Explanation:

The dependent variable is  the college students since it  is the variable we are going to measure as a result of the independent variable which is  the hazardous hazing ritual or non-hazardous hazing ritual.

8 0
3 years ago
Once potential energy is lost on a roller coaster it cannot be gained all the way back true or false
nignag [31]

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true

Explanation:

because the roller coaster can't work without energy

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3 years ago
A softball has a (positive/negative) acceleration when it is thrown. A soft ball has a (positive/negative) acceleration when it
Nadusha1986 [10]

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A softball has a (negative) acceleration when it is thrown. A soft ball has a (positive) acceleration when it is caughtExplanation:

8 0
3 years ago
A steel ball of mass 0.500 kg is fastened to a cord that is 70.0 cm long and fixed at the far end. The ball is then released whe
Liula [17]

Answer:

a) v₁fin = 3.7059 m/s   (→)

b) v₂fin = 1.0588 m/s     (→)

Explanation:

a) Given

m₁ = 0.5 Kg

L = 70 cm = 0.7 m

v₁in = 0 m/s   ⇒  Kin = 0 J

v₁fin = ?

h<em>in </em>= L = 0.7 m

h<em>fin </em>= 0 m   ⇒    U<em>fin</em> = 0 J

The speed of the ball before the collision can be obtained as follows

Einitial = Efinal

⇒ Kin + Uin = Kfin + Ufin

⇒ 0 + m*g*h<em>in</em> = 0.5*m*v₁fin² + 0

⇒ v₁fin = √(2*g*h<em>in</em>) = √(2*(9.81 m/s²)*(0.70 m))

⇒ v₁fin = 3.7059 m/s   (→)

b)  Given

m₁ = 0.5 Kg

m₂ = 3.0 Kg

v₁ = 3.7059 m/s    (→)

v₂ = 0 m/s

v₂fin = ?

The speed of the block just after the collision can be obtained using the equation

v₂fin = 2*m₁*v₁ / (m₁ + m₂)

⇒  v₂fin = (2*0.5 Kg*3.7059 m/s) / (0.5 Kg + 3.0 Kg)

⇒  v₂fin = 1.0588 m/s     (→)

7 0
4 years ago
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