Work in general is given by W=F·d where F is the force vector and d is the displacement vector. The dot symbol is the dot product which is a measure of how parallel two vectors are. It can be replaced by the cosine of the angle between the two vectors and the vectors replaced by their magnitudes. If F and d are parallel then the angle is zero and the cosine is unity. So in this case work can be defined as the product of the magnitudes of the force and distance:
W=Fd
Answer:
4m/s^2
Explanation:
mass(m)=20 kg
force=80 N
acceleration (a)=?
Therefore,
Force = mass * acceleration
80 = 20*a
a=80/20
=4m/s^2
<span>160 Joules
For this problem, we can ignore the vertical component of the applied force and focus on only the horizontal component of 80 N and since work is defined as force over distance, let's multiply the force by the distance:
80 N * 2.0 m = 160 Nm = 160 kg*m^2/s^2 = 160 Joules.
So the cart has a final kinetic energy of 160 Joules.</span>
Answer:
Acceleration = (change in speed) / (time for the change)
Change in speed = (ending speed) - (beginning speed)
= (3,600 mi/hr) - ( 0 )
= 3,600 mi/hr
= same as 1 mile/second.
Acceleration = (1 mi/sec) / (10 sec)
= 0.1 mi/sec² .
But 1 mile = 5,280 ft,
so
0.1 mi/s² = 528 ft/s²
Explanation:
have a great day
