Let’s arrange the fist equation
x+y=12
2x+3y=29
Multiply equation 1 by 2
So it will be
2x+2y=24
Subtract eq 1 from eq 2
2x+3y=29
2x+2y=24
—————-
Y =5
Put value of y in eq 1
2x+2y=24
2x +10= 24
2x= 24-10
2x= 14
x=14/2
x=7
S.S= (7,5)
Answer:
f(5) = 17
Step-by-step explanation:
You just plug in 5 for x:
f(5) = 3(5) + 2
f(5) = 15 +2
f(5) = 17
Hope this helps!
The function in this problem should be: <span>f(x) =x</span>² <span>+ 12x + 6
y = x</span>² + 12x + 6
y - 6 = x² + 12x
x² ⇒ x * x
12x ⇒ 2*6*x
missing number is 6² = 36
y - 6 + 36 = x² + 12x + 36
(x+6)(x+6) ⇒ x(x+6)+6(x+6) ⇒ x² + 6x + 6x + 36 = x² + 12x + 36
y + 30 = x² + 12x + 36
y = (x+6)² - 30
Choice is D. 36,-36
Answer:
B
Step-by-step explanation:
First calculate BD using sine ratio in Δ BCD and the exact value
sin60° = 
, thus
sin60° = 
= 
= 
= ( cross- multiply )
2BD = 12
( divide both sides by 2 )
BD = 6
-----------------------------------------------------------
Calculate AD using the tangent ratio in Δ ABD and the exact value
tan30° = 
, thus
tan30° = 
= 
= 
= ( cross- multiply )
AD = 6 ( divide both sides by )
AD = 6 → B
7 x² + 7 y² - 28 x + 42 y - 35 = 0 /: 7
x² + y² - 4 x + 6 y - 5 = 0
( x² - 4 x + 4 ) + ( y² + 6 y + 9 ) - 4 - 9 - 5 = 0
The equation in the standard form is:
( x - 2 )² + ( y + 3 )² = 18
The center is at the point ( 2, - 3 ).
Its radius is: √18 = 3√2 units.
