Answer:
2(3n)
Step-by-step explanation:
so you need to get the length of two side first!
the first side is <em>n</em> and the second is 2 times bigger so it means the length of the second side is <em>2n</em>
after you add them together you can get <em>3n</em>, so just times 2 for the whole square!
so you can get 2(3n) now!
hope it'll help! good night!
check the picture below.
so, the rocket will come back to the ground when h(t) = 0, thus
![\bf h(t)=-3t^2+12t\implies \stackrel{h(t)}{0}=-3t^2+12t\implies 0=-3t(t-4)\\\\[-0.35em]~\dotfill\\\\0=-3t\implies 0=t\impliedby \textit{0 seconds when it took off from the ground}\\\\[-0.35em]~\dotfill\\\\0=t-4\implies 4=t\impliedby \textit{4 seconds later, it came back down}](https://tex.z-dn.net/?f=%5Cbf%20h%28t%29%3D-3t%5E2%2B12t%5Cimplies%20%5Cstackrel%7Bh%28t%29%7D%7B0%7D%3D-3t%5E2%2B12t%5Cimplies%200%3D-3t%28t-4%29%5C%5C%5C%5C%5B-0.35em%5D~%5Cdotfill%5C%5C%5C%5C0%3D-3t%5Cimplies%200%3Dt%5Cimpliedby%20%5Ctextit%7B0%20seconds%20when%20it%20took%20off%20from%20the%20ground%7D%5C%5C%5C%5C%5B-0.35em%5D~%5Cdotfill%5C%5C%5C%5C0%3Dt-4%5Cimplies%204%3Dt%5Cimpliedby%20%5Ctextit%7B4%20seconds%20later%2C%20it%20came%20back%20down%7D)
A is an absolute value if it is greater than zero. This simply means that an absolute value number will always be greater than zero. This is because absolute value is the distance from 0 on a number line. Keep in mind that distance cannot be negative. For example, look at the numbers 5 and -5. 5 is 5 spaces from 0, and -5 is also 5 spaces from 0, not -5 spaces from 0. Put simply, an absolute value number that is greater than 0, will always be positive.
Feel free to mark Brainliest!
Answer:
(3a³)²=9a^6
3×3×a×a×a×a×a×a = 9a^6
that is your answer. plz Mark me brainliest
