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2 years ago

5. A ball is thrown upward with an initial velocity of 50 feet per second. The

Mathematics

1 answer:

dangina [55]2 years ago

7 0

Answer:

SEE BELOW IN BOLD.

Step-by-step explanation:

h = -16t^2 + 50t

h = 20 t

When the height is the same:

-16t^2 + 50t = 20t

-16t^2 + 30t = 0

t(-16t + 30) = 0

t = 0 or -16t + 30 = 0, so:

t = 0 or -30/-16 = 1.875

So the answer is 1.88 seconds to the nearest hundredth.

For the ball

h = -16t^2 + 50t

Finding the derivative and equating to zero:

dh/dt = -32t + 50 = 0

t = -50/-32 = 1.563

Maximum height after 1.56 seconds to nearest hundredth

When the ball hits the ground h = 0 so

-16t^2 + 50t = 0

-16t(t - 50/16)= 0

T = 3.13 SECONDS TO THE NEAREST HUNDERDTH

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3 years ago

What is the solution of √x-5 = x-11

PIT_PIT [208]

Hey!

To solve x in this equation we must first add five to both sides to get $\sqrt{x}$ on its own.

Original Equation :
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New Equation {Added 5 to Both Sides} :
$\sqrt{x} =x-6$

Now we must square both sides of the equation.

Old Equation :
$\sqrt{x} =x-6$

New Equation {Changed by Squaring Both Sides} :
$x= x^{2} -12x+36$

And now we must solve the new equation.

Step 1 - Switch sides
$x^{2} -12x+36=x$

Step 2 - Subtract x from both sides
$x^{2} -12x+36-x=x-x$

Step 3 - Simplify
$x^{2} -13x+36=0$

Now we need to solve the rest of the equation using the quadratic formula.

$\frac{-(-13)+ \sqrt{(-13) ^{2}-4*1*36 } }{2*1}$

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$\frac{13+ \sqrt{25}}{2}$

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$\frac{13+5}{2}$

$\frac{18}{2}$

9

$\frac{-(-13)- \sqrt{(-13) ^{2} -4*1*36} }{2*1}$

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Hope this helps!

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3 years ago

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Answer:

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Step-by-step explanation:

n(e)=2

n(s)=5

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2 years ago

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