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AleksandrR [38]
3 years ago
9

What is the slope of the line?

Mathematics
2 answers:
lilavasa [31]3 years ago
6 0

Answer:

-3

Step-by-step explanation:

First, you look at which way it is going. From left to right, the line is going down, so the slope is negative. Change in y is 3 and change in x is 1. From any two points on the line, the y value changes by 3 every time the x value changes by 1.

blsea [12.9K]3 years ago
3 0

Answer:

-3

Step-by-step explanation:

slope = rise/run

rise = vertical distance

run = horizontal distance

Step 1. Find two easy to read points on the line. Use points on intersections of grid lines.

For example, choose points (0, -3) and (-1, 0).

Step 2. Start at one point, say (0, -3). We must go to the other point using only vertical and horizontal moves. Go up 3 units. That is a rise of +3. It's positive 3 since up is positive. Now go left 1 unit. That is a run of -1. It is negative because going left is negative.

Step 3.

slope = rise/run

slope = 3/(-1) = -3

Answer: slope = -3

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Answer:

The probability hat the sample mean height for the 40 chimneys is greater than 102 meters is 0.1469.

Step-by-step explanation:

Let the random variable <em>X</em> be defined as the height of chimneys in factories.

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The standard deviation of heights is, <em>σ</em> = 12 meters.

It is provided that a random sample of <em>n</em> = 40 chimney heights is obtained.

According to the Central Limit Theorem if we have an unknown population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample means is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample means is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

Since the sample selected is quite large, i.e. <em>n</em> = 40 > 30, the central limit theorem can be used to approximate the sampling distribution of sample mean heights of chimneys.

\bar X\sim N(\mu_{\bar x},\ \sigma^{2}_{\bar x})

Compute the probability hat the sample mean height for the 40 chimneys is greater than 102 meters as follows:

P(\bar X>102)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}})>\frac{102-100}{12/\sqrt{40}})

                    =P(Z>1.05)\\=1-P(Z

*Use a <em>z</em>-table fr the probability.

Thus, the probability hat the sample mean height for the 40 chimneys is greater than 102 meters is 0.1469.

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