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ser-zykov [4K]
1 year ago
13

Solve using the pathagorean theorem​

Mathematics
1 answer:
Sergio039 [100]1 year ago
8 0

Answer:

A^(2) + B^(2) = C^(2)?????????????

Step-by-step explanation:

that's an isosceles triangle, not a right-angle triangle

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Evan, Claire, Jaya and Tim are running a 3km relay race.
Kruka [31]

Answer:

Tim needs to finish 59/90

Step-by-step explanation:

Add together what Evan Claire and Jaya ran  

9/10 + 7/9+ 2/3

The common denominator is 90

9/10 (9/9) +7/9 *10/10  + 2/3 *30/30

81/90 + 70/90 + 60/90

211/90

We need 3 km = 3 *90/90 = 270 /90

270/90 - 211/90 = 59/90

5 0
3 years ago
Triangles PIC Included
ZanzabumX [31]

Answer:

sin70° = x/6

Step-by-step explanation:

When we draw out our picture and triangle, we should see that our angle is on the ground 70°, the height <em>x</em> is across from the angle and is the vertical leg up, and that our hypotenuse is equal to 6:

sin70° = x/6

6 0
3 years ago
Read 2 more answers
Guys do anybody know the answer to this????????????????
sergejj [24]

Answer:

find where they intersect on the graph or find each line's individual equation and set them equivalent to eachother. x=2

8 0
3 years ago
I don't understand how to go about solving this equation more specifically the "y". Any help is appreciated. (:
Archy [21]

Answer:

y^2/x^6

apply exponent rule:

x^-2/x^4=1/x^4-(-2)=y/y^-1 x^4 -(-2)

then you subtract 4-(-2)=6

y/x^6 y^-1

cancel out the common factor: y^-1 and you get

y^2

------

x^6

6 0
2 years ago
All rhombus have all sides that are equal in length but which one are rhombus or not. Need help on this. ​
Artyom0805 [142]

Answer:

I think that the first one is not a rhombus but the last two are.

7 0
3 years ago
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