Solve using the pathagorean theorem

Mathematics

1 answer:

Sergio039 [100]2 years ago

8 0

Answer:

A^(2) + B^(2) = C^(2)?????????????

Step-by-step explanation:

that's an isosceles triangle, not a right-angle triangle

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A paper company produces 675,000 tissues and 1,250 boxes in 5 days.

SashulF [63]

The tissue production unit rate is _675000/5=135000_ tissues per day. 

The box production unit rate is_1250/5=250_ boxes per day. 

The paper company produces_135000/250=540_ times as many tissues per day as boxes per day.

4 0

3 years ago

I don't need you to work it out, just theorem(s) i need to reach the answer :)

VikaD [51]

Not sure why such an old question is showing up on my feed...

Anyway, let $x=\tan^{-1}\dfrac43$ and $y=\sin^{-1}\dfrac35$ . Then we want to find the exact value of $\cos(x-y)$ .

Use the angle difference identity:

$\cos(x-y)=\cos x\cos y+\sin x\sin y$

and right away we find $\sin y=\dfrac35$ . By the Pythagorean theorem, we also find $\cos y=\dfrac45$ . (Actually, this could potentially be negative, but let's assume all angles are in the first quadrant for convenience.)

Meanwhile, if $\tan x=\dfrac43$ , then (by Pythagorean theorem) $\sec x=\dfrac53$ , so $\cos x=\dfrac35$ . And from this, $\sin x=\dfrac45$ .

So,

$\cos\left(\tan^{-1}\dfrac43-\sin^{-1}\dfrac35\right)=\dfrac35\cdot\dfrac45+\dfrac45\cdot\dfrac35=\dfrac{24}{25}$

7 0

4 years ago

A physics exam consists of 9 multiple-choice questions and 6 open-ended problems in which all work must be shown. If an examinee

Mariana [72]

Answer:

The questions and problem can be chosen in 1260 ways.

Step-by-step explanation:

Given that, a physics exam consists of 6 open-ended problem and 9 multiple choice questions.

The order of choosing does not matter.

So,we use combination to find ways.

The ways to choose 6 multiple choice from 9 is= $^9C_6$