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loris [4]
2 years ago
10

A pet store has 10 puppies, including 4 poodles, 3 terriers and 3 retrievers. If Rebecca and Aaron in that order each select one

puppy at random with replacement (they may both select the same one) find the probability that they both select a poodle.
Mathematics
1 answer:
VikaD [51]2 years ago
5 0
4/20, 20% chance. The store has 20 puppies. Out of them is 4 poodles. Divide 4 by the total(20). And you get 0.2, remove the decimal place and add it in front of the 0 .02 reverse the numbers 20. Replace the period with a %.
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jenny has 68 1/2 pages of her left to read. How many pages will she have left after she reads 26 1/6 pages?
jekas [21]

Answer:

42 1/3

Step-by-step explanation:

We subtract 26 1/6 from 68 1/2. We do this by finding the LCM of 6 and 2. That is 6. We multiply 1/2 by 3/3 to get 3/6. Now, we subtract. 68 - 26 is 42, and 3/6 - 1/6 is 2/6. Our answer is 42 2/6. That can be simplified to 42 1/3.

6 0
3 years ago
3. Which of the following cannot be the side of a right angle triangle
Olegator [25]

Answer:

it’s b.

Step-by-step explanation:

(6)^2+(8)^2is not equal to (11)^2

7 0
2 years ago
One bar of candy A and two bars of candy B have 774 calories. Two bars of candy A and one bar of candy B contains 786 calories.
vampirchik [111]
◆ Define the variables:

Let the calorie content of Candy A = a
and the calorie content of Candy B = b

◆ Form the equations:

One bar of candy A and two bars of candy B have 774 calories. Thus:

a + 2b = 774

Two bars of candy A and one bar of candy B contains 786 calories

2a + b = 786

◆ Solve the equations:

From first equation,
a + 2b = 774
=> a = 774 - 2b

Put a in second equation
2×(774-2b) + b = 786
=> 2×774 - 2×2b + b = 786
=> 1548 - 4b + b = 786
=> -3b = 786 - 1548
=> -3b = -762
=> b = -762/(-3) = 254 calorie

◆ Find caloric content:

Caloric content of candy B = 254 calorie

Caloric content of candy A = a = 774 - 2b = 774 - 2×254 = 774 - 508 = 266 calorie
5 0
3 years ago
Demerol 45mg and atropine 400mcg/ml give how much per ml to total volume to inject demerol contains 50mg/ml, atropine contains 4
OverLord2011 [107]

Answer:

Volume injected  = 1.65 ml

Step-by-step explanation:

mass of Demerol =45 mg.

density of pre-filled in syringe = 50 mg/ml

Volume = 45/50 = 0.9 ml

For atropine mass = 0.3 mg

density= 400 mcg/ml     [ Note : 1 mcg = 0.001 mg]

volume filled  = 0.3/400(0.001) = 0.75 ml

So, the total volume filled = 0.75+0.9 = 1.65 ml

6 0
3 years ago
List 5 numbers with a mean of 5
givi [52]

If their mean is 5, then the numbers add up to 25.
Here are a few sets that do the job:
 
1, 2, 3, 4, 15

10, 20, 30, 40, -75

+2,  -2,  +99,  -99,  25

1,  5,  5,  5,  9

6 0
3 years ago
Read 2 more answers
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