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2 years ago

Which of the following produces an image that is not congruent to the pre-image?

Mathematics

1 answer:

34kurt2 years ago

8 0

Answer:

Dilation

Step-by-step explanation:

it’s a dilation because the dilation changes how big the image is or what it looks like after the original image.

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412.638 in expanded form using fractions and decimals (5th)

RoseWind [281]

i think its 400+10+2+.6+.03+0.008

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3 years ago

The sales tax in your city is 4.4%4.4\%4.4%4, point, 4, percent, and an item costs $3\$3$3dollar sign, 3 before tax.

olya-2409 [2.1K]

We are given original cost of the item excluding tax = $3.

Sale tax is 4.4% of the original cost of the item.

We need to round it to the nearest hundredth or cent.

So, we need to round 0.132 to two decimal places.

Therefore, 0.132 can be round to 0.13.

We needed to find the tax amount on the original cost of the item.

<h3>Therefore, $ 0.13 tax would you pay on that item of $3.</h3>

4 0

4 years ago

Read 2 more answers

Kesha threw her baton up in the air from the marching band platform during practice. The equation h(t) = −16t² + 54t + 40 gives

lapo4ka [179]

Answer:

a) 40 feet

b) 54 ft/min

c) 4 mins

Step-by-step explanation:

Solution:-

- Kesha models the height ( h ) of the baton from the ground level but thrown from a platform of height hi.

- The function h ( t ) is modeled to follow a quadratic - parabolic path mathematically expressed as:

h ( t ) = −16t² + 54t + 40

Which gives the height of the baton from ground at time t mins.

- The initial point is of the height of the platform which is at a height of ( hi ) from the ground level.

- So the initial condition is expressed by time = 0 mins, the height of the baton h ( t ) would be:

h ( 0 ) = hi = -16*(0)^2 + 54*0 + 40

h ( 0 ) = hi = 0 + 0 + 40 = 40 feet

Answer: The height of the platform hi is 40 feet.

- The speed ( v ) during the parabolic path of the baton also varies with time t.

- The function of speed ( v ) with respect to time ( t ) can be determined by taking the derivative of displacement of baton from ground with respect to time t mins.

v ( t ) = dh / dt

v ( t )= d ( −16t² + 54t + 40 ) / dt

v ( t )= -2*(16)*t + 54

v ( t )= -32t + 54

- The velocity with which Kesha threw the baton is represented by tim t = 0 mins.

Hence,

v ( 0 ) = vi = -32*( 0 ) + 54

v ( 0 ) = vi = 54 ft / min

Answer: Kesha threw te baton with an initial speed of vo = 54 ft/min

- The baton reaches is maximum height h_max and comes down when all the kinetic energy is converted to potential energy. The baton starts to come down and cross the platform height hi = 40 feet and hits the ground.

- The height of the ball at ground is zero. Hence,

h ( t ) = 0

0 = −16t² + 54t + 40

0 = -8t^2 + 27t + 20

- Use the quadratic formula to solve the quadratic equation:

$t = \frac{27+/-\sqrt{27^2 - 4*8*(-20)} }{2*8}\\\\t = \frac{27+/-\sqrt{1369} }{16}\\\\t = \frac{27+/-37 }{16}\\\\t = \frac{27 + 37}{16} \\\\t = 4$