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Umnica [9.8K]
2 years ago
9

What are the solutions of x2 = 8 – 5x? startfraction 5 minus startroot 57 endroot over 2 endfraction comma startfraction 5 start

root 57 endroot over 2 endfraction startfraction negative 5 minus startroot 57 endroot over 2 endfraction comma startfraction negative 5 startroot 57 endroot over 2 endfraction startfraction negative 47 over 4 endfraction comma startfraction 67 over 4 endfraction startfraction negative 67 over 4 endfraction comma startfraction 47 over 4 endfraction
Mathematics
2 answers:
kondor19780726 [428]2 years ago
5 0

The solution of the given quadratic equation are,

x=\frac{-5-\sqrt{57} }{2},x=\frac{-5+\sqrt{57} }{2}

The equation to solve is given as

x^2=-5x+8

Rearrange the given equation in standard form, ax^2+bx+c=0

where,  a,b and c are constants.

Therefore, we add 5x-8 on both sides to get,

x^2+5x-8=0

Here, a=1,b=5 and c=-8

The solution to the above equation is

<h3>What is the quadratic formula?</h3>

x=\frac{-b\±\sqrt{b^2-4ac} }{2a}

Use the value of a,b,c in the quadratic formula and solve for x

x=\frac{-5\±\sqrt{5^2-4(1)(-5)} }{2(1)}

x=\frac{-5\±\sqrt{25+35} }{2(1)}

x=\frac{-5\±\sqrt{57} }{2(1)}

Therefore, the solutions are

x=\frac{-5-\sqrt{57} }{2},x=\frac{-5+\sqrt{57} }{2}

To learn more about the quadratic equation visit:

brainly.com/question/25841119

Lemur [1.5K]2 years ago
3 0

Answer:

answer is b

Step-by-step explanation:

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Explanation:

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As for the other trig ratios, they are:

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