Question

What are the solutions of x2 = 8 – 5x? startfraction 5 minus startroot 57 endroot over 2 endfraction comma startfraction 5 startroot 57 endroot over 2 endfraction startfraction negative 5 minus startroot 57 endroot over 2 endfraction comma startfraction negative 5 startroot 57 endroot over 2 endfraction startfraction negative 47 over 4 endfraction comma startfraction 67 over 4 endfraction startfraction negative 67 over 4 endfraction comma startfraction 47 over 4 endfraction

Answer 1

The solution of the given quadratic equation are,

$x=\frac{-5-\sqrt{57} }{2}$,$x=\frac{-5+\sqrt{57} }{2}$

The equation to solve is given as

$x^2=-5x+8$

Rearrange the given equation in standard form, $ax^2+bx+c=0$

where,  a,b and c are constants.

Therefore, we add 5x-8 on both sides to get,

$x^2+5x-8=0$

Here, a=1,b=5 and c=-8

The solution to the above equation is

What is the quadratic formula?

$x=\frac{-b\±\sqrt{b^2-4ac} }{2a}$

Use the value of a,b,c in the quadratic formula and solve for x

$x=\frac{-5\±\sqrt{5^2-4(1)(-5)} }{2(1)}$

$x=\frac{-5\±\sqrt{25+35} }{2(1)}$

$x=\frac{-5\±\sqrt{57} }{2(1)}$

Therefore, the solutions are

$x=\frac{-5-\sqrt{57} }{2},x=\frac{-5+\sqrt{57} }{2}$

To learn more about the quadratic equation visit:

brainly.com/question/25841119

Answer 2

Answer:

answer is b

Step-by-step explanation: