Answer:
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If the polynomial is of the form x^2+bx+c (ie., no factor in front of the x^2!!) then you can look for numbers that add up to b and multiply to c.
So in this case: what two numbers, when added, give -2 and when multiplied, give 1? A little trial and error gives you -1 and -1.
So the factorization is (x-1)(x-1). This is zero for x=1. There is only one zero.
Where are the sets? I don't see any...
Answer: the number is -14
Step-by-step explanation: let the number be x
2(x+4) = x-6
2x+8 = x-6
2x-x = -6-8
x = -14
