Question

Use the given measures of the triangles to write the indicated trigonometric value. Then find the measure of the indicated angle to the nearest 100th of a degree

Answer 1

Answer: read the comments for extra added more accurate information this was in the comments and by HOZI3RSMUS3 so it’s not mine

We're suppose to measure the trigonometric values of the triangles and the values of indicates angles .For that,We need to know that,Sin θ = side opposite to angle  θ / HypotenuseCos θ = side adjacent to angle θ / HypotenuseTan  θ = side opposite to angle θ/side adjacent to angle θNow,In the first triangle,We're provided by,side opposite to angle  θ =QR =24side adjacent to angle θ = PR = 10Hypotenuse = PQ = 26So,Sin P = 24/26Cos P = 10/26Tan P = 24/10m∠P  = sin p° = 24/26m∠P= sin^-1(24/26)m∠P= 67.38 °In the second triangle,We're provided by,side opposite to angle  θ =MO =9side adjacent to angle θ = NO = 40Hypotenuse = MN= 41So,Sin N= 9/41Cos N= 40/41Tan N= 9/40m∠N  = sin N° = 9/41m∠N= sin^-1(9/41)m∠N= 12.68°In the third triangle,We're provided by,side opposite to angle  θ =AC =15side adjacent to angle θ = AB = 8Hypotenuse = BC = 17So,Sin B = 15/17Cos B = 8/17Tan B = 15/8m∠B  = sin p° = 15/17m∠B= sin^-1(15/17)m∠B= 61.93°In the fourth triangle,We're provided by,side opposite to angle  θ =BC =8side adjacent to angle θ = AC = 6Hypotenuse = AB = 10So,Sin A = 8/10Cos A = 6/10Tan A = 8/6m∠A  = sin p° = 8/10m∠A= sin^-1(8/10)m∠P= 53. °*53.13°

Step-by-step explanation: