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Nadusha1986 [10]
2 years ago
5

Use the given measures of the triangles to write the indicated trigonometric value. Then find the measure of the indicated angle

to the nearest 100th of a degree

Mathematics
1 answer:
Alja [10]2 years ago
4 0

Answer: read the comments for extra added more accurate information this was in the comments and by HOZI3RSMUS3 so it’s not mine


We're suppose to measure the trigonometric values of the triangles and the values of indicates angles .For that,We need to know that,Sin θ = side opposite to angle  θ / HypotenuseCos θ = side adjacent to angle θ / HypotenuseTan  θ = side opposite to angle θ/side adjacent to angle θNow,In the first triangle,We're provided by,side opposite to angle  θ =QR =24side adjacent to angle θ = PR = 10Hypotenuse = PQ = 26So,Sin P = 24/26Cos P = 10/26Tan P = 24/10m∠P  = sin p° = 24/26m∠P= sin^-1(24/26)m∠P= 67.38 °In the second triangle,We're provided by,side opposite to angle  θ =MO =9side adjacent to angle θ = NO = 40Hypotenuse = MN= 41So,Sin N= 9/41Cos N= 40/41Tan N= 9/40m∠N  = sin N° = 9/41m∠N= sin^-1(9/41)m∠N= 12.68°In the third triangle,We're provided by,side opposite to angle  θ =AC =15side adjacent to angle θ = AB = 8Hypotenuse = BC = 17So,Sin B = 15/17Cos B = 8/17Tan B = 15/8m∠B  = sin p° = 15/17m∠B= sin^-1(15/17)m∠B= 61.93°In the fourth triangle,We're provided by,side opposite to angle  θ =BC =8side adjacent to angle θ = AC = 6Hypotenuse = AB = 10So,Sin A = 8/10Cos A = 6/10Tan A = 8/6m∠A  = sin p° = 8/10m∠A= sin^-1(8/10)m∠P= 53. °*53.13°

Step-by-step explanation:

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The 9th and the 12th term of an arithmetic progression are 50 and 65 respectively. find the common difference
Rzqust [24]

The first term of the arithmetic progression exists at 10 and the common difference is 2.

<h3>How to estimate the common difference of an arithmetic progression?</h3>

let the nth term be named x, and the value of the term y, then there exists a function y = ax + b this formula exists also utilized for straight lines.

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The 9th and the 12th term of an arithmetic progression exist at 50 and 65 respectively.

9th term = 50

a + 8d = 50 ...............(1)

12th term = 65

a + 11d = 65 ...............(2)

subtract them, (2) - (1), we get

3d = 15

d = 5

If a + 8d = 50 then substitute the value of d = 5, we get

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a = 10.

Therefore, the first term is 10 and the common difference is 2.

To learn more about common differences refer to:

brainly.com/question/1486233

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