Answer:
The magnitud of the torque doing by the foot at the point where the shaft is attached is 0.063 Nm
Explanation:
The torque is obtained by multiplying the longitude from the shaft attached point to force acting point by the force perpendicular component:
T = d * Fp
Notice that the perpindicular component is the total force magnitud times the sino of the angle respect the horizontal:
Fp = F*sin(a)
Replacing the values for the force and the angle:
Fp = 33N*sin(π/5) = 33N * 0.011 = 0.363 N
Taking the distance in meters:
T = 0.2m * 0.363 N = 0.063 Nm
As the bumblebee approaches me, the frequency of sound becomes higher than the 152 Hz because of the velocity with which the bee approaches at 3 m/s.
The speed of the bee causes me to detect an increase of frequency higher than 152 Hz.
This phenomenon is called Doppler Effect.
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A 500 g ball swings in a vertical circle at the end of a 1.4-m-long string. when the ball is at the bottom of the circle, the tension in the string is 18 n.
Answer:
both magnitude and direction
Explanation:
The worker's pull on the handle of the cart is best described as the force having both magnitude and direction.
- This is a vector quantity
- The force is channeled to move the cart in a specific direction.
- Also, the pull on the cart can be quantified, and so it have magnitude.
- Most physical properties either have magnitude or direction or both.
In this case, the worker is pulling the cart towards a specified direction.
Therefore, the fitting choice is both magnitude and direction.
Answer:
5,760,000 lb-ft²/s²
Explanation:
Work done, W = mgy where m = mass of stone = 12,000 lb, g = 32 ft/s² and y = vertical distance = 15 ft.
So, W = mgy = 12,000 lb × 32 ft/s² × 15 ft. = 5,760,000 lb-ft²/s²
