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11111nata11111 [884]
3 years ago
7

Does an object which is positively charged contains all protons and no electrons?

Physics
2 answers:
uranmaximum [27]3 years ago
8 0

Answer:

The contain both protons and electrons, but they have more protons than electrons making it a positively charged object.

Aleonysh [2.5K]3 years ago
7 0

Answer:

Positively charged objects have electrons; they simply possess more protons than electrons.

Explanation:

2. An object that is electrically neutral contains only neutrons. Electrically neutral atoms simply possess the same number of electrons as protons.

<h3>Information:</h3>

If an atom has an equal number of protons and electrons, its net charge is 0. If it gains an extra electron, it becomes negatively charged and is known as an anion.

<h3>Tips:</h3>

If it loses an electron, it becomes positively charged and is known as a cation.

<h2>I hope this answers help you! :></h2>
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An object's
shusha [124]

The planet of an item will remain constant across the planet, but if you give it more mass, the gravitational force increases while the acceleration due to gravity remains constant.

<h3 /><h3>What is the difference between mass and weight?</h3>

The mass of the body is defined as the amount of matter a body has. It is denoted by m and its unit is kg. Mass is the quantity on which a lot of physical quantity depends.

Weight is defined as the amount of force an object exerts on the surface. It is given as the product of mass and the gravitational pull.

Mass is an independent quantity it never depends on the other. While weight is a dependent quantity that depends upon the gravitational pull.

The value of gravitational pull is different in the different parts of the universe. For example, on the earth, the value of gravitational acceleration is 9.81 m/sec².While on the moon it is g/6.

Weight is change according to the place or surrounding while the mass of the body is constant everywhere.

The planet of an item will remain constant across the cosmos, but if you give it more mass, the gravitational force increases while the acceleration of gravity remains constant.

If a planet's gravity weakens, the weight of that planet will likewise be altered. With an increase in mass, weight also rises.

Hence, the gravitational force increases while the acceleration due to gravity remains constant for the given case.

To learn more about the mass refer to the link;

brainly.com/question/19694949

#SPJ1

3 0
2 years ago
A person starts at a position of 16 meters and finishes at a position of
DochEvi [55]

Answer:

38 is a good girl and a great place to work for u and I miss you y and I miss you much love your love and love to

7 0
3 years ago
Two electric motors drive two elevators of equal mass in a three-story building 10 meters tall. Each elevator has a mass of 1,00
vaieri [72.5K]

Answer:

(C) Work=9.8×10⁴J

Explanation:

Given data

mass m=1000 kg

building height=10 m

To

Find work

Solution

As we know that:

Work=mass*gravity*height\\W=mgh\\W=(1000kg)*(9.8m/s^{2} )*(10m)\\W=9.8*10^{4}J

So option (C) is correct one

4 0
3 years ago
Do black holes have an internal structure? If so, how might the internal structure be probed?
oksian1 [2.3K]

Answer:

no

Explanation:

it can't be probed it would be like probing a goat's butt

5 0
3 years ago
Read 2 more answers
Consult Multiple-Concept Example 15 to review the concepts on which this problem depends. Water flowing out of a horizontal pipe
kiruha [24]

Answer:

The pressure of the water in the pipe is 129554 Pa.

Explanation:

<em>There are wrongly written values on the proposal, the atmospheric pressure must be 101105 Pa, and the density of water 1001.03 kg/m3, those values are the ones that make sense with the known ones.</em>

We start usign the continuity equation, and always considering point 1 a point inside the pipe and point 2 a point in the nozzle:

A_1v_1=A_2v_2

We want v_2, and take into account that the areas are circular:

v_2=\frac{A_1v_1}{A_2}=\frac{\pi r_1^2 v_1}{\pi r_2^2}=\frac{r_1^2 v_1}{r_2^2}

Substituting values we have (we don't need to convert the cm because they cancel out between them anyway):

v_2=\frac{r_1^2 v_1}{r_2^2}=\frac{(1.8cm)^2 (0.56m/s)}{(0.49cm)^2}=7.56m/s

For determining the absolute pressure of the water in the pipe we use the Bernoulli equation:

P_1+\frac{\rho v_1^2}{2}+\rho gh_1=P_2+\frac{\rho v_2^2}{2}+\rho gh_2

Since the tube is horizontal h_1=h_2 and those terms cancel out, so the pressure of the water in the pipe will be:

P_1=P_2+\frac{\rho v_2^2}{2}-\frac{\rho v_1^2}{2}=P_2+\frac{\rho (v_2^2-v_1^2)}{2}

And substituting for the values we have, considering the pressure in the nozzle is the atmosphere pressure since it is exposed to it we obtain:

P_1=101105 Pa+\frac{1001.03Kg/m^3 ((7.56m/s)^2-(0.56m/2)^2)}{2}=129554 Pa

3 0
3 years ago
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